PHP curl/json问题POST

问题描述:

我遇到了一个问题,试图从表单内发出POST到chargify API日志付款。PHP curl/json问题POST

但是,由于某种原因,它实际上是作为GET发送的,因为它返回了一个错误。

任何人都可以提供任何意见,我可能做错了什么?邮差工作正常工作发送与JSON身体POST,但我不能让它从PHP工作。

(注:<urlmaskedforprivacy>显然不是我的实际代码)

//find invoice id # using invoice number search form 
    $invoiceNumber = fRequest::get('invoicenumber'); 
    $json = file_get_contents('https://<maskedforprivacy>.chargify.com/invoices.json?number=' . $invoiceNumber); 
    $returnedInvData = fJSON::decode($json); 
    $invoiceId = $returnedInvData[0]->invoice->id; 


    // grab form data as payment info to send to chargify 
    $paymentAmount = fRequest::Get('amount'); 
    $memo = fRequest::Get('memo'); 

    if ((isset($invoiceNumber,$paymentAmount,$memo))) { 

    $url = 'https://<maskedforprivacy>.chargify.com/subscriptions/' . $invoiceId . '/payments.json'; 

    $params = array(
         'payment' => array(
          'amount' => $paymentAmount, 
          'memo' => (string)$memo 
        ), 
       ); 

    // encode as json    
    $content = FJSON::encode($params); 


    // send to chargify 
    $curl = curl_init($url); 
    curl_setopt($curl, CURLOPT_HEADER, false); 
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); 
    curl_setopt($curl, CURLOPT_HTTPHEADER, 
      array("Content-type: application/json")); 
    curl_setopt($curl, CURLOPT_POST, true); 
    curl_setopt($curl, CURLOPT_POSTFIELDS, $content); 

    $json_response = curl_exec($curl); 

    $status = curl_getinfo($curl, CURLINFO_HTTP_CODE); 

    if ($status != 201) { 
     die("Error: call to URL $url failed with status $status, response $json_response, curl_error " . curl_error($curl) . ", curl_errno " . curl_errno($curl)); 
    } 


    curl_close($curl); 

    $response = json_decode($json_response, true);  

    } 
+0

请张贴你得到的输出。 –

+0

错误404.但我知道的网址是好的,因为我可以张贴到它没有问题,使用邮递员和发送json在身体 – firecasey

我用这一个代码,但它会返回401错误,并要求基本身份验证。在json_response变量中。可能是你错过了吗?

$paymentAmount = 10; 
    $memo = 'test'; 



    $url = 'https://test.chargify.com/subscriptions/1/payments.json'; 

    $params = array(
         'payment' => array(
          'amount' => $paymentAmount, 
          'memo' => (string)$memo 
        ), 
       ); 

    // encode as json 
    $content = json_encode($params); 


    // send to chargify 
    $curl = curl_init($url); 

    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); 
    curl_setopt($curl, CURLOPT_HTTPHEADER, 
      array("Content-type: application/json")); 
    curl_setopt($curl, CURLOPT_POST, true); 
    curl_setopt($curl, CURLOPT_POSTFIELDS, $content); 

    $json_response = curl_exec($curl); 

    $status = curl_getinfo($curl, CURLINFO_HTTP_CODE); 

    if ($status != 201) { 
     die("Error: call to URL $url failed with status $status, response $json_response, curl_error " . curl_error($curl) . ", curl_errno " . curl_errno($curl)); 
    } 


    curl_close($curl); 

    $response = json_decode($json_response, true); 
+0

身份验证处理的URL使用://chargify.com ....我只是在我的隐私代码中掩盖了它。 – firecasey

+0

好吧 - 所以代码几乎和你的一样 - 我已经删除标题以全模式查看答案,并且没有404错误。你可以尝试相同的,并发送完整的答案,否则我认为这是不可能的,以帮助你。 – Vyacheslav