Bing地图v8事件传递不正确的引脚?
问题描述:
因此,我正在使用bing地图v8编写一个应用程序。不幸的是,它没有z-index支持(尽管有z-index函数...)。所以我正在尝试使用图层来完成类似的事情。问题是当我在层之间交换引脚时,事件开始在正确的引脚位置上触发错误的元数据。Bing地图v8事件传递不正确的引脚?
这里是我创建的引脚
function createImagePin(location, index, objArray)
{
var obj = objArray[index];
var smallPin = getSmallPin(obj);
var pin = new Microsoft.Maps.Pushpin(location,
{
visible: true,
icon: smallPin.data,
anchor: new Microsoft.Maps.Point(smallPin.width/2, smallPin.height/2) //Align center of pushpin with location.
});
pin.metadata = {};
pin.metadata.index = index;
pin.metadata.dataTarget = obj;
pin.metadata.isSelected = false;
Microsoft.Maps.Events.addHandler(pin, 'click', function (e) {
if(e.targetType === 'pushpin')
{
SetRowSelection(e.target.metadata.index);
}
});
Microsoft.Maps.Events.addHandler(pin, 'mouseover', function (e)
{
if(e.targetType === 'pushpin')
{
SelectPin(e.target);
ShowInfobox(e.target);
console.log(e.target.getLocation());
}
});
Microsoft.Maps.Events.addHandler(pin, 'mouseout', function (e)
{
if (e.targetType === 'pushpin')
{
DeselectPin(e.target);
HideInfobox();
}
});
return pin;
}
出于某种原因,我把每一个具有正确的位置,但不正确的元数据时得到一个脚物件在鼠标悬停。如果我评论取消选择...我得到正确的两个。
这是我如何选择和取消选择引脚。基于我给出的例子Bing Maps pushpin icon issues
还有没有其他代码触摸这些引脚的时刻......这似乎很奇怪我。它几乎就像内部它只是复制图层中的一些信息,而不是移动附加到对象的所有项目。事实上,如果我只是注释掉添加/删除它会阻止向我传递不正确的数据......尽管我失去了Z-indexing。
function SelectPin(pin)
{
switch (pin.metadata.dataTarget.ComparableType)
{
case "Subject":
mapLayers.subjectLayer.remove(pin);
pin.setOptions({ visible: true, icon: largeGreenHouse.data, anchor: new Microsoft.Maps.Point(largeGreenHouse.width/2, largeGreenHouse.height/2) });
break;
case "Listing Comp":
mapLayers.compLayer.remove(pin);
pin.setOptions({ visible: true, icon: largeBlueHouse.data, anchor: new Microsoft.Maps.Point(largeBlueHouse.width/2, largeBlueHouse.height/2) });
break;
case "Sales Comp":
mapLayers.compLayer.remove(pin);
pin.setOptions({ visible: true, icon: largeBlueHouse.data, anchor: new Microsoft.Maps.Point(largeBlueHouse.width/2, largeBlueHouse.height/2) });
break;
case "Hidden":
pin.setOptions({ visible: false });
return;
default:
mapLayers.observableLayer.remove(pin);
pin.setOptions({ visible: true, icon: largeGreyHouse.data, anchor: new Microsoft.Maps.Point(largeGreyHouse.width/2, largeGreyHouse.height/2) });
break;
}
mapLayers.selectionLayer.add(pin);
pin.metadata.isSelected = true;
}
function DeselectPin(pin)
{
if(!pin.metadata.isSelected)
return;
pin.metadata.isSelected = false;
mapLayers.selectionLayer.remove(pin);
switch (pin.metadata.dataTarget.ComparableType)
{
case "Subject":
pin.setOptions({ visible: true, icon: greenHouse.data, anchor: new Microsoft.Maps.Point(greenHouse.width/2, greenHouse.height/2) });
mapLayers.subjectLayer.add(pin);
break;
case "Listing Comp":
pin.setOptions({ visible: true, icon: blueHouse.data, anchor: new Microsoft.Maps.Point(blueHouse.width/2, blueHouse.height/2) });
mapLayers.compLayer.add(pin);
break;
case "Sales Comp":
pin.setOptions({ visible: true, icon: blueHouse.data, anchor: new Microsoft.Maps.Point(blueHouse.width/2, blueHouse.height/2) });
mapLayers.compLayer.add(pin);
break;
case "Hidden":
pin.setOptions({ visible: false });
return;
default:
pin.setOptions({ visible: true, icon: greyHouse.data, anchor: new Microsoft.Maps.Point(greyHouse.width/2, greyHouse.height/2) });
mapLayers.observableLayer.add(pin);
break;
}
答
嗯,它似乎是一个数据问题而不是代码问题。我的数据将被地理编码为相同的纬度/长度,用于某些不具有相同地址的属性。因此,阵列的重新排列会导致不同的位置,同一个位置会获得“顶部位置”。