IOS UIView的跳转
#pragma mark返回当前UIView的UIController - (UIViewController *)funResponderVC{ UIView *net = [super superview]; // 返回上一级的视图。直到找到UIViewController视图为止 UIResponder *nextResponder = [next nextResponder]; if ([nextResponder isKindOfClass:[UIViewController class]]) { return (UIViewController *)nextResponder; } else{ return nil; } }
UIViewController *vc = [[UIViewController alloc] init];
[[self funResponderVC] presentViewController:vc animated:YES completion:nil];
这样就实现了UIVIew的跳转,其实可以写在UIViewController,不必这么麻烦,可是考虑到代码的封装性以及代码后期的修改,所以遇到在UIVIew的跳转是必不可少的。