用句号替换所有非字母数字
问题描述:
我试图在从*机构收到的数据框中重命名所有这些残酷的列名。用句号替换所有非字母数字
> colnames(thedata)
[1] "Region" "Resource Assessment Site ID"
[3] "Site Name/Facility" "Design Head (feet)"
[5] "Design Flow (cfs)" "Installed Capacity (kW)"
[7] "Annual Production (MWh)" "Plant Factor"
[9] "Total Construction Cost (1,000 $)" "Annual O&M Cost (1,000 $)"
[11] "Cost per Installed Capacity ($/kW)" "Benefit Cost Ratio with Green Incentives"
[13] "IRR with Green Incentives" "Benefit Cost Ratio without Green Incentives"
[15] "IRR without Green Incentives"
列标题包含特殊的非字母数字字符和空格,因此不可能引用它们,因此我必须重命名它们。我想用句号替换所有非字母数字字符。但我想:
old.col.names <- colnames(thedata)
new.col.names <- gsub("^a-z0-9", ".", old.col.names)
的^是一个“不”的划分,所以我认为这将取代一切,是不是字母与在old.col.names一个时期。
任何人都可以帮忙吗?
答
这里有三个问题需要考虑:
make.names(x)
gsub("[^A-Za-z0-9]", ".", x)
names(janitor::clean_names(setNames(data.frame(matrix(NA, ncol = length(x))), x)))
这里的每一个样子:
make.names(x)
## [1] "Region" "Resource.Assessment.Site.ID"
## [3] "Site.Name.Facility" "Design.Head..feet."
## [5] "Design.Flow..cfs." "Installed.Capacity..kW."
## [7] "Annual.Production..MWh." "Plant.Factor"
## [9] "Total.Construction.Cost..1.000..." "Annual.O.M.Cost..1.000..."
## [11] "Cost.per.Installed.Capacity....kW." "Benefit.Cost.Ratio.with.Green.Incentives"
## [13] "IRR.with.Green.Incentives" "Benefit.Cost.Ratio.without.Green.Incentives"
## [15] "IRR.without.Green.Incentives"
gsub("[^A-Za-z0-9]", ".", x)
## [1] "Region" "Resource.Assessment.Site.ID"
## [3] "Site.Name.Facility" "Design.Head..feet."
## [5] "Design.Flow..cfs." "Installed.Capacity..kW."
## [7] "Annual.Production..MWh." "Plant.Factor"
## [9] "Total.Construction.Cost..1.000..." "Annual.O.M.Cost..1.000..."
## [11] "Cost.per.Installed.Capacity....kW." "Benefit.Cost.Ratio.with.Green.Incentives"
## [13] "IRR.with.Green.Incentives" "Benefit.Cost.Ratio.without.Green.Incentives"
## [15] "IRR.without.Green.Incentives"
library(janitor)
names(clean_names(setNames(data.frame(matrix(NA, ncol = length(x))), x)))
## [1] "region" "resource_assessment_site_id"
## [3] "site_name_facility" "design_head_feet"
## [5] "design_flow_cfs" "installed_capacity_kw"
## [7] "annual_production_mwh" "plant_factor"
## [9] "total_construction_cost_1_000" "annual_o_m_cost_1_000"
## [11] "cost_per_installed_capacity_kw" "benefit_cost_ratio_with_green_incentives"
## [13] "irr_with_green_incentives" "benefit_cost_ratio_without_green_incentives"
## [15] "irr_without_green_incentives"
的样本数据:
x <- c("Region", "Resource Assessment Site ID", "Site Name/Facility",
"Design Head (feet)", "Design Flow (cfs)", "Installed Capacity (kW)",
"Annual Production (MWh)", "Plant Factor", "Total Construction Cost (1,000 $)",
"Annual O&M Cost (1,000 $)", "Cost per Installed Capacity ($/kW)",
"Benefit Cost Ratio with Green Incentives", "IRR with Green Incentives",
"Benefit Cost Ratio without Green Incentives", "IRR without Green Incentives")
你需要'[^ [:alnum:] ] +' – akrun
你可以尝试'make.names(colnames(thedata),allow_ = FALSE)' – Jimbou
试试'pattern =“[^ a-zA-Z0-9]”'。显示正则表达式是非常重要的,你需要'['和']'之间的任何组合。 '^'也必须在该模式旁边。祝你好运! –