Jar忽略所有方法
我正在制作一个非常简单的jar来解压缩zip并运行其中的jar。我遇到的问题是它根本没有做任何事情。Jar忽略所有方法
这是jar的主要和唯一类文件。清单确实指向它,并加载没有错误。
import java.io.File;
import java.io.IOException;
import java.io.OutputStream;
import java.io.FileWriter;
import java.io.BufferedWriter;
import java.io.BufferedOutputStream;
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.FileOutputStream;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.InputStream;
import java.io.InputStreamReader;
import static java.lang.Integer.parseInt;
import java.net.URLConnection;
import java.net.URL;
import java.util.zip.ZipFile;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
import java.util.Enumeration;
import sign.signlink;
import java.nio.file.*;
import java.io.FileReader;
public class ClientUpdater {
private String fileToExtractNew = "/client.zip";
private String getJarDir() throws FileNotFoundException, IOException{
String linebuf="",verStr="";
FileInputStream fis = new FileInputStream("/runLocationURL.txt");
BufferedReader br= new BufferedReader(new InputStreamReader(fis));
while ((linebuf = br.readLine()) != null) {
verStr = linebuf;
}
return verStr;
}
public static void main(String[] args) {
System.out.println("start");
}
private void unZip() {
System.out.println("unzipping");
try {
ZipEntry zipEntry;
//client
BufferedInputStream bufferedInputStreamNew = new BufferedInputStream(new FileInputStream(this.fileToExtractNew));
ZipInputStream zipInputStreamNew = new ZipInputStream(bufferedInputStreamNew);
//client
while ((zipEntry = zipInputStreamNew.getNextEntry()) != null) {
String stringNew = zipEntry.getName();
File fileNew = new File(this.getJarDir() + File.separator + stringNew);
if (zipEntry.isDirectory()) {
new File(this.getJarDir() + zipEntry.getName()).mkdirs();
continue;
}
if (zipEntry.getName().equals(this.fileToExtractNew)) {
this.unzipNew(zipInputStreamNew, this.fileToExtractNew);
break;
}
new File(fileNew.getParent()).mkdirs();
this.unzipNew(zipInputStreamNew, this.getJarDir() + zipEntry.getName());
}
zipInputStreamNew.close();
}
catch (Exception var1_2) {
var1_2.printStackTrace();
}
}
private void unzipNew(ZipInputStream zipInputStreamNew, String stringNew) throws IOException {
System.out.println("unzipping new");
FileOutputStream fileOutputStreamNew = new FileOutputStream(stringNew);
byte[] arrby = new byte[4024];
int n = 0;
while ((n = zipInputStreamNew.read(arrby)) != -1) {
fileOutputStreamNew.write(arrby, 0, n);
}
fileOutputStreamNew.close();
Runtime.getRuntime().exec("java -jar " + getJarDir() + "/Project Pk Client.jar");
System.exit(0);
}
}
它显示“开始”消息,但不显示其他2,因此它永远不会到达这些方法。是因为他们没有被召唤?我仍然在学习Java。
您实际上必须从main
调用其他方法。现在,你要告诉计算机要做的就是打印start
然后退出。函数不会简单地通过现有的方式被调用。
看起来你快速浏览一下,你只需要在你的main
函数中加上unzip();
,就在System.out.println
之后。
要做到这一点,你需要说的是,其他方法是static
,所以你需要说private static void unZip()
而不是private void unZip()
。对于其他方法也要这样做。
import java.io.*;
import static java.lang.Integer.parseInt;
import java.net.URLConnection;
import java.net.URL;
import java.util.zip.ZipFile;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
import java.util.Enumeration;
import sign.signlink;
import java.nio.file.*;
public class ClientUpdater {
private String fileToExtractNew = "/client.zip";
private static String getJarDir() throws FileNotFoundException, IOException{
String linebuf="",verStr="";
FileInputStream fis = new FileInputStream("/runLocationURL.txt");
BufferedReader br= new BufferedReader(new InputStreamReader(fis));
while ((linebuf = br.readLine()) != null) {
verStr = linebuf;
}
return verStr;
}
public static void main(String[] args) {
System.out.println("start");
unZip();
}
private static void unZip() {
System.out.println("unzipping");
try {
ZipEntry zipEntry;
//client
BufferedInputStream bufferedInputStreamNew = new BufferedInputStream(new FileInputStream(this.fileToExtractNew));
ZipInputStream zipInputStreamNew = new ZipInputStream(bufferedInputStreamNew);
//client
while ((zipEntry = zipInputStreamNew.getNextEntry()) != null) {
String stringNew = zipEntry.getName();
File fileNew = new File(this.getJarDir() + File.separator + stringNew);
if (zipEntry.isDirectory()) {
new File(this.getJarDir() + zipEntry.getName()).mkdirs();
continue;
}
if (zipEntry.getName().equals(this.fileToExtractNew)) {
this.unzipNew(zipInputStreamNew, this.fileToExtractNew);
break;
}
new File(fileNew.getParent()).mkdirs();
this.unzipNew(zipInputStreamNew, this.getJarDir() + zipEntry.getName());
}
zipInputStreamNew.close();
}
catch (Exception var1_2) {
var1_2.printStackTrace();
}
}
private static void unzipNew(ZipInputStream zipInputStreamNew, String stringNew) throws IOException {
System.out.println("unzipping new");
FileOutputStream fileOutputStreamNew = new FileOutputStream(stringNew);
byte[] arrby = new byte[4024];
int n = 0;
while ((n = zipInputStreamNew.read(arrby)) != -1) {
fileOutputStreamNew.write(arrby, 0, n);
}
fileOutputStreamNew.close();
Runtime.getRuntime().exec("java -jar " + getJarDir() + "/Project Pk Client.jar");
System.exit(0);
}
}
我知道这会很简单。非常感谢你。 :) – VirtualJunky
@VirtualJunky你很欢迎:)。如果答案是令人满意的,请考虑将其标记为未来访问者的正确答案。 – Jashaszun
是的,我正在尝试,但一直告诉我,我需要等待1分钟出于某种原因。但现在明白了! – VirtualJunky
好吧,那就是我的想法。那么我该如何解决这个问题呢?我试着添加unZip();到主要的方法,但它说,我不能调用一个静态的静态方法。就我的知识达到这一点而言。 :D – VirtualJunky