如何使用FINDSTR从robocopy日志文件中去除％行？

Question

我想从我的robocopy日志文件中去除所有具有％progress-value的行。该线路是这样的：

  *EXTRA Datei   7.3 g test.pst 
      Neuer     7.3 g huge.PST 
    0.0% 
    0.0% 
    0.0% 
    0.1% 
    0.1% 
    0.1% 
    0.1% 
99.8% 
99.9% 
99.9% 
99.9% 
99.9% 
99.9% 
100% 
      Neue Datei   7.5 g another.PST 
    0.0% 

我不是成功的，这种尝试

FINDSTR.exe /V "%" LogFile.txt > LogFileWithoutPercentageLines.txt 

因为这减少过多行范围（在上面的例子与huge.PST和another.PST整条生产线）

％-lines包含0.0％之前的两个空格和一个CR。
％-lines包含10.0％之前的一个空格和一个CR。
％-line在100.0％之前不包含空格，但在100％之后包含两个空格和一个CR。

我该如何摆脱这个毫无用处的0.0％，直到只有FINDSTR的100％行？

Answer 1

使用robocopy with /NP switch，CF 记录选项在robocopy /?：

/NP :: No Progress - don't display percentage copied. 

例如，robocopy "%_source%" "%_target%" /log:"%temp%\38610436.log" /NP

然而，接下来的评论脚本表示去除一切不必要的可能方式从现有的杂草出没日志文件（findstr本身不足以对这个复杂的任务）：

@ECHO OFF >NUL 
SETLOCAL EnableExtensions DisableDelayedExpansion 

set "_source=d:\bat\odds and ends\B"  rem change to match your circumstances 
set "_target=d:\bat\odds and ends\Bcopy" rem detto 
set "_logFileRawData=%temp%\38610436.log" rem detto 
set "_logFileCleaned=%temp%\38610436a.log" rem detto 

rem /NP : No Progress - don’t display % copied 
rem robocopy "%_source%" "%_target%" /log:"%temp%\38610436.log" /NP 
    robocopy "%_source%" "%_target%" /log:"%temp%\38610436.log" 

>"%_logFileCleaned%" (
    for /f "usebackq tokens=1,* delims=:" %%G in (`findstr /N "^" "%_logFileRaw%"`) do (
    set "_line=%%H" 
    call :strip_Progress 
    SETLOCAL EnableDelayedExpansion 
     echo(!_line! 
    ENDLOCAL 
) 
) 
ENDLOCAL 
goto :eof 

:strip_Progress 
set "_zero="      rem zero percent indicator 
set "_line=%_line%"    rem remove all Carriage Return characters 
    rem after above command, _line with progress could be, excluding Square Brackets: 
    rem [New File    0 ZeroFile.ext100% ] 
    rem [New File   51808 TinyFile.txt 0% 100% ] 
    rem [Newer    1.1 m Mid_File.ext 0% 21% 42% 64% 85% 100% ] 
    rem [New File  162.1 m Big_File.ext 0.0% 0.6% 1.2% … 99.3% 99.9%100% ] 
if "%_line%"=="" goto :eof 
if "%_line:~-6%"=="100%% " call :removeProgress 
goto :eof 

:removeProgress 
set "_line=%_line:~0,-6%"   rem strip six trailing characters 
if defined _zero goto :eof 
    rem as yet, zero percent indicator not set 
:stripTrailingSpace 
if "%_line:~-2%"==" " set "_line=%_line:~0,-1%" & goto :stripTrailingSpace 
if "%_line:~-4%"==" 0%%" set "_zero=4" & set "_line=%_line%x%%" 
if "%_line:~-6%"==" 0.0%%" set "_zero=6" 
if "%_line:~-1%"=="%%" goto :removeProgress 
goto :eof 

更多资源（必读的，不完全）：

• （命令参考）An A-Z Index of the Windows CMD command line
• （有益的特殊性）Windows CMD Shell Command Line Syntax
• （%G,%H等特殊页面）Command Line arguments (Parameters)
• （特殊页）EnableDelayedExpansion
• （>，&等特殊页）Redirection
• （%_line:~0,-6%等）Extract part of a variable (substring)
• （%%一倍百分号）Escape Characters, Delimiters and Quotes