电脑操作系统不能使用fs登录系统API
我正在为Computercraft操作Windows 8模拟操作系统,而我的登录系统无法正常工作。我一直试图弄清楚过去一小时左右的情况,这真的令人沮丧。电脑操作系统不能使用fs登录系统API
这里的登录代码:
-- Log-in and User Definition Service
--- Variables
userExists = fs.exists("/Users/.config/userConfig.cfg")
termx, termy = term.getSize()
halfx = math.floor(termx*0.5)
halfy = math.floor(termy*0.5)
prompt = "Welcome"
uprompt = "Username: "
pprompt = "Password: "
userConfig = fs.open("/Users/.config/userConfig.cfg", "r")
edituserConfig = fs.open("/Users/.config/userConfig.cfg", "w")
--- Functions
function login(user)
if user == "admin" then
term.setCursorPos(1,1)
term.setTextColor(256)
print (user)
elseif user == "guest" then
print (user)
else
print ("nil")
end
end
function userCheck()
if userExists == true then
term.clear()
term.setBackgroundColor(8)
term.setCursorPos(halfx-0.5*#prompt, halfy - 4)
term.clear()
print (prompt)
term.setCursorPos((halfx-#uprompt), (halfy - 2))
write (uprompt)
term.setCursorPos((halfx-#uprompt), (halfy - 1))
write (pprompt)
term.setCursorPos((halfx), (halfy - 2))
upin = read()
term.setCursorPos((halfx), (halfy - 1))
ppin = read("*")
if upin == userConfig.readLine(21) and ppin == userConfig.readLine(24) then
print ("ADMIN")
elseif upin == userConfig.readLine(33) and ppin == userConfig.readLine(36) then
login("guest")
end
elseif userExists == false then
elseif userExists == nil then
end
end
--- Main
userCheck()
userConfig.cfg:
-- Format as follows:
--
-- (name):
--
-- (prop):
-- "(value)"
--
-- (prop):
-- "(value)"
--
-- (prop):
-- "(value)"
--
--
-- (name):
-- [etc.]
Admin:
user:
"Admin"
pass:
"admin"
auth:
"1"
Guest:
user:
"Admin"
pass:
nil
auth:
"0"
Root:
user:
nil
pass:
nil
auth:
"2"
的readLine不接受参数,只读取下一行。你最好的选择是使用表和textutils.serialize把它全部写到一个文件中,然后在阅读时使用textutils.unserialize把它放在一个表中。
联系:
user:
"Admin"
pass:
"admin"
auth:
"1"
可以在表内写如
{
Admin = {
user = "Admin"
pass = "admin"
auth = "1"
}
Guest = {
user = "Admin"
pass = nil
auth = "0"
}
}
这会工作得在你想要的方式,并允许更多的变化和扩展。当然,从中读取是一个不同的故事,我会使用一个函数来查找和发送授权码,否则无法使用。
如
local function findUsers(username,password)
--This will read the file and put all it's data inside a table, and then close it.
local file = fs.open("userConfig.cfg","r")
local userRanks = textutils.unserialize(file.readAll())
file.close()
--To read all the data in a table, i'm going to do this.
for a,v in pairs(userRanks) do
if type(v) == "table" then
if userRanks[a].user == username and userRanks[a].pass == password then
return userRanks[a].auth
end
end
end
--[[If we look through the entire file table, and the username and password aren't the same
as on file, then we say we couldn't find it by returning nil]]--
return nil
end
现在您的输入区域所有你需要做的是,当他们输入用户名和密码,只需拨打这个事后,也如果让你拥有授权码
local auth = findUsers(upin,ppin)
--If they inputted an actual username and password
if auth ~= nil then
--If the auth code from the rank is "1"
if auth == "1" then
--Do whatever stuff you want
elseif auth == "2" then
--Do whatever other stuff for this auth code
end
elseif auth == nil then
print("Oh no you inputted an invalid username and/or password, please try again!"
end
主要是因为我无法评论David的帖子,所以我没有Oeed:P 是的,你的版本可以工作David但是他使用的格式看起来很像一张表格会使它工作。 – Flamanis 2014-10-12 10:11:09
为了扩展Dragon53535的回答是:
这里有一个快速例行我扔在一起,读取文件到表:
local function fileToTable(path)
-- first we make sure that the path can be opened
assert(fs.exists(path), path..' does not exist!')
assert(not fs.isDir(path), path..' is a directory!')
local tSrc = {}
local inFile = fs.open(path, 'r')
-- we set line to a non-nil value
local line = ''
-- we continue the loop until line is nil
while line do
-- we read a line from the file
line = inFile.readLine()
-- now we save the value of line to our table
-- line will be nil at EOF
tSrc[#tSrc+1] = line
end
inFile.close()
return tSrc
end
运行后userConfig = fileToTable('/Users/.config/userConfig.cfg')
,您可以用userConfig[24]
替换userConfig.readLine(24)
之类的东西。
或者,你可以检查出io library的CC's implementation。这是一个标准的Lua库(尽管在CC中它是一个fs包装),所以代码可以更容易地从CC移出。 特别是,io.lines()
在这里会很有帮助。
上面的代码改写为使用io.lines
:
local function fileToTable(path)
-- first we make sure that the path can be opened
assert(fs.exists(path), path..' does not exist!')
assert(not fs.isDir(path), path..' is a directory!')
local tSrc = {}
-- iterate over file
-- io.lines is neat, since it opens and closes the file automatically
for line in io.lines(path) do
tSrc[#tSrc+1] = line
end
return tSrc
end
正如你所看到的,这是小得多(代码只有9行!)和更易于管理。 CC不是我的首选解决方案的原因是io
位于fs
之上,所以最好移除中间人。
希望这会有所帮助。
修正了龙的用户名。我以为你是Oeed,因为他说他会看这个帖子,哈哈 – skwerlman 2014-10-12 10:15:37
它不起作用?预期的结果是什么?究竟发生了什么? – 2014-10-06 02:55:26
@ColonelThirtyTwo它可以打印我想要的所有内容,但在输入凭据后,似乎无法检查它们是否正确。我将编辑问题以包含屏幕截图和“userConfig.cfg”文件。 – user3377520 2014-10-06 20:38:15
对不起,我的声望对屏幕不够高,但如果您有电脑设备或模拟器,您可以测试代码,只需确保文件位于代码中定义的正确目录中即可。 – user3377520 2014-10-06 20:58:12