Matlab：拟合曲线时在parfor中工作for-loop中断

Question

希望你能帮助我解决这个错误。我使用交叉验证机制运行一些代码以适应曲线年龄。我重复曲线拟合1000次以评估最佳拟合。

我定义我的模型为：

linear_ft = fittype({'x', '1'}); 
monotonic_ft= fittype({'-1/x', '1'}); 
quadratic_ft = fittype('poly2'); 

我然后运行下面通过数据分割的不同选择进行迭代，记录残差以下曲线拟合...

Data = randn(4,300,10,10); 
Ages = randn(300,1); 

for thisDim1 = 1:4 
    for thisDim2 = 1:10 
     for thisDim3 = 1:10 
      for nIts = 1:1000 
       RandomOrder = randperm(300,300); 
       Fit_Subs = RandomOrder(1:length(Ages)/2); % Take random subs to fit to 
       Test_Subs = RandomOrder(length(Ages)/2+1:300); % Take random subs to test fit to 

       Fit_Data = squeeze(Data(thisDim1,Fit_Subs,thisDim2,thisDim3)); % Take data to fit to 
       Test_Data = squeeze(Data(thisDim1,Test_Subs,thisDim2,thisDim3)); % Take data to test fit 

       Fit_Ages = Ages; 
       Fit_Ages(Fit_Subs) = []; %Take ages of Fit Subs only 
       Test_Ages = Ages; 
       Test_Ages(Test_Subs) = []; % Take ages of Test Subs only 

       Nsubs = (length(Ages)/2); 

       % Model Data using Curves 
       fFit_Lin = fit(Fit_Ages,Fit_Data',linear_ft); 
       fFit_Mon = fit(Fit_Ages,Fit_Data',monotonic_ft); 
       fFit_Quad = fit(Fit_Ages,Fit_Data',quadratic_ft); 

       % Fit Modelled Data to Test Data 
       tFit_Lin = fFit_Lin(Test_Ages); 
       tFit_Mon = fFit_Mon(Test_Ages); 
       tFit_Quad = fFit_Quad(Test_Ages); 

       % Calculate Median Residual 
       Lin_Med_Resid(nIts) = median(tFit_Lin - Test_Data'); 
       Mon_Med_Resid(nIts) = median(tFit_Mon - Test_Data'); 
       Quad_Med_Resid(nIts) = median(tFit_Quad - Test_Data'); 

      end 
     end 
    end 
end 

如果您用第四个循环（nIts）作为for循环运行它。如果你运行它作为一个PARFOR环也不会指出错误：

Error using fit>iFit (line 264) The name 'lower' is not an accessible property for an instance of class 'llsqoptions'.

Error in fit (line 108) [fitobj, goodness, output, convmsg] = iFit( xdatain, ydatain, fittypeobj, ...

没有人有任何想法如何解决这一问题？我会非常感谢任何建议！

感谢，

本

Answer 1

尝试重新启动MATLAB或打字clear all，看它是否清除事情你。

你的代码适用于我，但并行工具箱可以是我的经验有点挑剔。