简单的方法来显示Ajax？
问题描述：
我有6个控制器的功能，由ASC和DESC 3场命令。简单的方法来显示Ajax？
功能：
public function orderByIdAsc(){
$projects = DB::table('projects')->orderBy('id','asc')->get();
return view('cms.public.views.projects.menu', ['projects' => $projects]);
}
public function orderByIdDesc(){
$projects = DB::table('projects')->orderBy('id','desc')->get();
return view('cms.public.views.projects.menu', ['projects' => $projects]);
}
public function orderByOrderAsc(){
$projects = DB::table('projects')->orderBy('order','asc')->get();
return view('cms.public.views.projects.menu', ['projects' => $projects]);
}
public function orderByOrderDesc(){
$projects = DB::table('projects')->orderBy('order','desc')->get();
return view('cms.public.views.projects.menu', ['projects' => $projects]);
}
public function orderByPublicAsc(){
$projects = DB::table('projects')->orderBy('public','asc')->get();
return view('cms.public.views.projects.menu', ['projects' => $projects]);
}
public function orderByPublicDesc(){
$projects = DB::table('projects')->orderBy('public','desc')->get();
return view('cms.public.views.projects.menu', ['projects' => $projects]);
}
与她的6条航线也：
Route::prefix('admin')->group(function() {
Route::get('project/orderByIdAsc', ['uses' => '[email protected]', 'as' => 'admin.projects.orderByIdAsc']);
Route::get('project/orderByIdDesc', ['uses' => '[email protected]', 'as' => 'admin.projects.orderByIdDesc']);
Route::get('project/orderByOrderAsc', ['uses' => '[email protected]', 'as' => 'admin.projects.orderByOrderAsc']);
Route::get('project/orderByOrderDesc', ['uses' => '[email protected]', 'as' => 'admin.projects.orderByOrderDesc']);
Route::get('project/orderByPublicAsc', ['uses' => '[email protected]', 'as' => 'admin.projects.orderByPublicAsc']);
Route::get('project/orderByPublicDesc', ['uses' => '[email protected]', 'as' => 'admin.projects.orderByPublicDesc']);
});
目前我打电话给这里的功能：
<th><a href="{{ route('admin.projects.orderByIdAsc')}}"><span class="glyphicon glyphicon-arrow-up" id="orderByIdAsc"></span></a>Id<a href="{{ route('admin.projects.orderByIdDesc')}}"><span class="glyphicon glyphicon-arrow-down" id="orderByIdDesc"></span></a></th>
<th>Slug</th>
<th><a href="{{ route('admin.projects.orderByOrderAsc')}}"><span class="glyphicon glyphicon-arrow-up" id="orderByOrderAsc"></span></a>Order<a href="{{ route('admin.projects.orderByOrderDesc')}}"><span class="glyphicon glyphicon-arrow-down" id="orderByOrderDesc"></span></a></th>
<th><a href="{{ route('admin.projects.orderByPublicAsc')}}"><span class="glyphicon glyphicon-arrow-up" id="orderByPublicAsc"></span></a>Public<a href="{{ route('admin.projects.orderByPublicDesc')}}"><span class="glyphicon glyphicon-arrow-down" id="orderByPublicDesc"></span></a></th>
任何方式Ajax来做到这一点比制作6个div更容易隐藏/显示它？
非常感谢！
答
对于这种情况，你有两个选择：
- 第一招：使用路径参数
可以将所有路线结合起来，一个下令：
Route::prefix('admin')->group(function() {
Route::get('project/order/{field}/{order}', [
'uses' => '[email protected]',
'as' => 'admin.projects.order'
]);
});
在您的AdminController：
public function order($field, $order)
{
$projects = DB::table('projects')->orderBy($field,$order)->get();
return view('cms.public.views.projects.menu')
->withProjects($projects);
}
在视图：
<a href="{{ route('admin.projects.order', ['field' => 'id', 'order' => 'asc']) }}">Order by ID</a>
- 第二个：使用查询字符串
对于路线：
Route::prefix('admin')->group(function() {
Route::get('project/order', [
'uses' => '[email protected]',
'as' => 'admin.projects.order'
]);
});
在你AdminController：
public function order(\Illuminate\Http\Request $request)
{
$order = $request->query('order');
$field = $request->query('field');
$projects = DB::table('projects')->orderBy($field,$order)->get();
return view('cms.public.views.projects.menu')
->withProjects($projects);
}
并在视图：
<a href="{{route('admin.projects.order', ['field' => 'id', 'order' => 'desc'])}}">Order by ID</a>
做所有这些返回的数据相同，只是下令不同？那么你的页面一遍又一遍地请求相同的数据？是的，有一个更简单的方法来做到这一点。请求数据*一次*并根据需要在JavaScript中进行分类。或者你在问别的吗？这不是很清楚。 – David
其中一个选项是使用Route :: get（'project/orderBy/{field_name}/{asc_desc}'并在Request中获得这些参数。这样，您只需要一个路由和一个方法。 –
是的，是你可以向我解释如何用JS做这件事吗？非常感谢 –