查找字典中的所有常用值和子常用值

Question

我是在python中使用dicitonaries的新功能。我手边有一个简单的问题。我有一个名为“输入”的口号。

Input={'VAR1':['K1','K2','K3','K4','K5...'], 
'VAR2':['K3','K4',...], 
'VAR3':['K2','K4','K5',...]} 

词典“输入”中的键数量可能会有所不同。我渴望的输出是让所有常用值的列表，我想获得小组共同价值观作为字典

'K4' string common in all the lists (for all key values) 
'K3' is only present in the list with key'VAR1' and 'VAR2'. 

所以它帮助，如果我有相应的键

输出：

Common_Value=['K4',....] 

Subcommon_Values1=['VAR1':['K3....'],'VAR2':['K3....']] 
Subcommon_values2=['VAR1':['K5',...],'VAR3':['K5',....]] 

任何人都可以帮助我吗？

谢谢

Answer 1

这将让你所有的共同的价值观：

sect = None 
for k,v in Input.items(): 
    if sect == None: 
     sect = set(v) 
    else: 
     sect = sect.intersection(set(v)) 
Common_Value = list(sect) 

直到你清楚你的不同SubCommonValues结果和他们的实际结构（你似乎有列表中的键）之间的差异，不能确定这是你想不想要的：

all = None 
for k,v in Input.items(): 
    if all == None: 
     all = set(v) 
    else: 
     all = all.union(set(v)) 
diff = all.difference(sect) 
uncom = { x:list() for x in diff } 
for x in diff: 
    for k,v in Input.items(): 
     if x in v: 
      uncom[x].append(k) 
grps = {} 
for k,v in uncom.items(): 
    kv = tuple(v) 
    if kv not in grps: 
     grps[kv] = [k] 
    else: 
     grps[kv].append(k) 
for k,v in grps.items(): 
    print({ x:v for x in k }) 

Answer 2

，你可以这样做：

result=[i for i in Input if "K4" in Input[i]] 

例子：

>>> Input={'VAR1':['K1','K2','K3','K4','K5'],'VAR2':['K3','K5'],'VAR3':['K2','K4','K5']} 
>>> result=[i for i in Input if "K4" in Input[i]] 
>>> result 
['VAR1', 'VAR3'] 

编辑：

也许是这样的：

commonValues=['K4', 'K2'] 
result=[i for i in Input if set(commonValues).issubset(set(Input[i]))] 

这将返回key列表中你Inputdict包含commonValues列表的所有元素...