PHP检查单选按钮,然后输出名称和价格

问题描述:

我有几个单选按钮,A和B.两个都有四个单选按钮。 我的代码现在回显所选单选按钮的值,但这不是我想要的。我想要检查哪个按钮被选中,然后回显产品的名称和价格。PHP检查单选按钮,然后输出名称和价格

<!DOCTYPE html> 
<html> 
    <head> 
    <title>Ordering System</title> 

<!-- include css file here--> 
    <link rel="stylesheet" href="css/style.css"/> 

    </head> 

    <body> 

<?php 

//prices of Radio A 
    $A1 = 10; 
    $A2 = 20; 
    $A3 = 30; 
    $A4 = 50; 
//prices of Radio B 
    $B1 = 20; 
    $B2 = 30; 
    $B3 = 40; 
    $B4 = 50; 
?> 


    <div class="container"> 
     <div class="main"> 
     <h2>A or B</h2><hr/> 
     <form method="post" action="form.php"> 
     <hr/> 

     <!---------Radio Button's starts here------> 
     <label class="heading">A:</label><br/> 
      <input type="radio" name="A" value="A1">Name Of Product A1<br/> 

      <input type="radio" name="A" value="A2">Name Of Product A2<br/> 

      <input type="radio" name="A" value="A3">Name Of Product A3<br/> 

      <input type="radio" name="A" value="A4">Name Of Product A4<br/><br/> 

     <label class="heading">B:</label><br/> 
      <input type="radio" name="B" value="B1">Name Of Product B1<br/> 

      <input type="radio" name="B" value="B2">Name Of Product B2<br/> 

      <input type="radio" name="B" value="B3">Name Of Product B3<br/> 

      <input type="radio" name="B" value="B4">Name Of Product B4<br/><br/> 


      <?php 
       if (isset($_POST['submit'])) { 

       if(isset($_POST['A'])) 
       { 
       echo "First selection:<b> ".$_POST['A']."</b> <br>" ; 
       } 
       else{ echo "<span>Please choose.</span>";} 
       } 

       if (isset($_POST['submit'])) { 

       if(isset($_POST['B'])) 
       { 
       echo "Second Selection:<b> ".$_POST['B']."</b>"; 
       } 
       else{ echo "<span>Please choose.</span>";} 
       } 

        $radio = $_POST['A']; 
        if ($radio == 'A1') { 
        echo $A1} 
        ?> 

      <hr/> 
      <input type="submit" name="submit" value="Order" /> 

     </form> 
     </div> 
    </div> 

    </body> 
</html> 

当然我GOOGLE了当我得到这个问题,我发现这一点。但是,当我像上面实现它时,这给我一个错误

错误: (!)解析错误:语法错误,意外'}',期待','或';'在C:\ WAMP \ WWW \上线OK \ form.php的78

<?php 
    $radio = $_POST['RadioName']; 
    if ($radio == 'Value') { 
    echo "Print The Price Here"} 
?> 

后来我发现:但是这给我的错误:(!) 解析错误:语法错误,意外 '}',期待',' 要么 ';'在C:\ WAMP \ WWW \ OK \ form.php的上线81

<?php 
if ($_SERVER['REQUEST_METHOD'] === 'POST') 
{ 
    if ($_POST['RadioName'] == "Value") 
    { 
     echo "" 
    } 
    else if ($_POST['RadioName'] == "Value2") 
    { 
     echo "" 
    } 
} 
?> 

时等来实现:

<?php 
if ($_SERVER['REQUEST_METHOD'] === 'POST') 
{ 
    if ($_POST['A'] == "A1") 
    { 
     echo $A1 
    } 
    else if ($_POST['A'] == "A2") 
    { 
     echo $A2 
    } 
} 
?> 

是否有另一种解决方案?或者这些解决方案中的任何一种都可以调整,以便它们能够工作?

+0

你在echo $ A1后缺少分号,它应该是echo $ A1;在线78 – 2014-10-20 09:44:25

知道无线电选项虽然是一组自己与名称相同,但多值,并在$ _POST数组只有名称和值可

尝试使用子类像checkedselected,使用jQuery。