无法在Outlook电子邮件的Python

问题描述：

提取收件人的名字，我试图提取收件人地址，我得到下面的时候我打印：无法在Outlook电子邮件的Python

<COMObject <unknown>>

我有下面的代码。我也试过Receipient.Name。

import win32com.client 
import sys 
import csv 


outlook = win32com.client.Dispatch("Outlook.Application").GetNamespace("MAPI") 
inbox = outlook.GetDefaultFolder(6) 
messages = inbox.Items 
message = messages.GetLast() 
subject_list = [] 
sender_list = [] 
recipients_list = [] 
i = 0 

while message: 

    subject = message.Subject 
    sender = message.SenderName 
    recipients = message.Recipients 


    subject_list.append(str(subject)) 
    sender_list.append(str(sender)) 
    recipients_list.append(recipients) 
    i+=1 

    message = messages.GetPrevious() 
    if i > 10: 
     break 

for subject in subject_list: 
    print(subject) 
for sender in sender_list: 
    print(sender) 
for recipient in recipients_list: 
    print(recipient)

如何获取收件人姓名或电子邮件地址？

答

我认为“message.Recipients”会让你成为Recipient Collection，而不是特定的收件人。您可以通过将集合中的单个收件人添加到您的列表中来解决此问题。

要获取电子邮件地址，如果地址将地址作为Exchange用户提供给您，则可能需要一些额外的导航，因此您可以使用Address Entry中的函数来检索它。（您可以通过浏览这些链接中的msdn文档来了解关于这些Outlook对象的更多信息。）

我在代码中添加了几行代码，以下代码适用于我。

while message: 

    subject = message.Subject 
    sender = message.SenderName 
    recipients = message.Recipients 

    subject_list.append(str(subject)) 
    sender_list.append(str(sender)) 
    #This loop will add each recipient from an email's Recipients Collection to your list individually 
    for r in recipients: 
     recipients_list.append(r) 
    i+=1 

    message = messages.GetPrevious() 
    if i > 10: 
     break 

for subject in subject_list: 
    print(subject) 
for sender in sender_list: 
    print(sender) 
for recipient in recipients_list: 
    #Now that the for loop has gone into the Recipient Collection, this should print the recipient name 
    print(recipient) 
    #This is the "Address", but for me they all appeared as Exchange Users, rather than explicit email addresses. 
    print(recipient.Address) 
    #I used this code to get the actual addresses 
    print(recipient.AddressEntry.GetExchangeUser().PrimarySmtpAddress)

无法在Outlook电子邮件的Python

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