连接QAction插槽
问题描述:
我想了解为什么QObject :: connect有时做这项工作,为什么有时它不。连接QAction插槽
我会很高兴anykind的帮助下,我已经做了很多的谷歌/文档阅读/和寻找问题的可能dublicates,重复的情况下,并没有解决我的问题
我有2个的Qt项目非常相似的代码,并且从几个小时我试图找出为什么它不工作。
工作testproject:
toolbar.h
#ifndef TOOLBAR_H
#define TOOLBAR_H
#include <QMainWindow>
#include <QApplication>
class Toolbar : public QMainWindow
{
Q_OBJECT
public:
Toolbar(QWidget *parent = 0);
public slots:
void dosmt();
signals:
void test();
void test2();
private:
static bool button1;
};
#endif // TOOLBAR_H
toolbar.cpp
#include "toolbar.h"
#include <QToolBar>
#include <QIcon>
#include <QAction>
#include <QLabel>
#include <iostream>
bool Toolbar::button1=false;
Toolbar::Toolbar(QWidget *parent): QMainWindow(parent)
{
QString path="../res/login_photo.png";
QPixmap newpix(path);
QPixmap openpix("../res/global.png");
QPixmap quitpix("new.png");
QToolBar *toolbar = addToolBar("main toolbar");
QAction *hallo=toolbar->addAction(QIcon(newpix), "1");
toolbar->addAction(QIcon(openpix), "Open File");
toolbar->addSeparator();
QAction *quit = toolbar->addAction(QIcon(quitpix),
"Quit Application");
connect(hallo,SIGNAL(triggered()),this,SLOT(dosmt()));
connect(quit, SIGNAL(triggered()), qApp, SLOT(quit()));
}
void Toolbar::dosmt()
{
button1=!button1;
if(button1){
emit test();
}else{
emit test2();
}
}
现在我想改善的布局,这样我可以把所有的元素我可能需要所以我做了一个新的项目,如果我评论不工作的连接信号插槽线,工作。工具栏basicly刚刚更名为主窗口
#ifndef MAINWINDOW_H
#define MAINWINDOW_H
#include <QMainWindow>
#include <QApplication>
class MainWindow : public QMainWindow
{
Q_OBJECT
public:
MainWindow(QWidget *parent = 0);
~MainWindow();
public slots:
void dosmt();
void h1();
signals:
void s1();
};
mainwindow.cpp
#include "mainwindow.h"
#include <QVBoxLayout>
#include <QToolBar>
#include <QApplication>
#include <QObject>
MainWindow::MainWindow(QWidget *parent)
: QMainWindow(parent)
{
QPixmap newpix("../res/login_photo.png");
QPixmap openpix("../res/global.png");
QPixmap quitpix("new.png");
QToolBar *toolbar = new QToolBar;
QAction* hallo=toolbar->addAction(QIcon(newpix), "Page1");
toolbar->addAction(QIcon(openpix), "Open File");
QAction *quit = toolbar->addAction(QIcon(quitpix),"Quit Application");
这里是低于
connect(hallo,SIGNAL(triggered()),this,SLOT(h1()));
没有问题,我的问题时出现错误消息:
connect(this,SIGNAL(s1()),this,SLOT(h1()));
其余:
QVBoxLayout * mvbox = new QVBoxLayout;
mvbox->addWidget(toolbar);
setCentralWidget(new QWidget);
centralWidget()->setLayout(mvbox);
}
void MainWindow::dosmt()
{
qDebug("happ");
}
void MainWindow::h1()
{
qDebug("happ");
}
MainWindow::~MainWindow()
{
}
误差(Fehler)消息:
/cpp/qt/GUItest1/mainwindow.cpp:19:
Fehler: no matching function for call to 'MainWindow::connect(QAction*&, const char*, MainWindow* const, const char*)'
connect(hallo,SIGNAL(triggered()),this,SLOT(h1()));
followed by a bunch of not helping stuff i just took the ones that look remotly usefull
Qt/5.4/gcc_64/include/QtCore/qobject.h:213: Fehler:
no type named'Object' in 'struct QtPrivate::FunctionPointer<const char*>'
^
/Qt/5.4/gcc_64/include/QtCore/qobject.h:254: Fehler: invalid use of incomplete type 'struct QtPrivate::QEnableIf<false, QMetaObject::Connection>'
/Qt/5.4/gcc_64/include/QtCore/qglobal.h:1056: Fehler: declaration of 'struct QtPrivate::QEnableIf<false, QMetaObject::Connection>'
template <bool B, typename T = void> struct QEnableIf;
^
/Qt/5.4/gcc_64/include/QtCore/qobject.h:293:
Fehler: no type named 'Object' in 'struct QtPrivate::FunctionPointer<const char*>'
通过播放围绕我发现,问题出信号的QAction内,因为从主窗口信号可以从连接到插槽主窗口
项目一和二之间的唯一区别似乎是如何添加工具栏
addToolBar
VS
QToolBar *toolbar = new QToolBar; and
mvbox->addWidget(toolbar);
答
答
为什么不使用SLOTS
?
toolbar = addToolBar("main toolbar");
toolbar->addAction("Open", this, SLOT(open_file()));
toolbar->addAction("New", this, SLOT(new_file());
toolbar->addAction("Quit", this, SLOT(quit_application());
而在header
:
[...]
public slots:
void open_file();
void new_file();
void quit_application();
[...]
SLOTS是QT最佳实践,您应该使用它们。
为什么要访问'toolbar-> hallo','toobar'对象没有一个叫做hallo的属性。即使您将它添加为小孩,它也是在相同的范围内定义的。所以使用'conenct(hallo,....);' – 2015-04-05 06:13:22
是啊我知道经过几个小时的尝试,我有创意,这是最后一次尝试修复它发布之前发布变回更好,但不工作版本 – Philipp 2015-04-05 06:15:35
connect(this ,SIGNAL(S1()),对此,SLOT(H1()));工作正常,但与QAction对象,它不工作 – Philipp 2015-04-05 06:21:21