无法调用我的方法在数组类型int []
问题描述:
我目前正在学习如何使用遗传算法。不过,我的方法compareTo()
有困难。这种方法应该比较两个人之间的适应值。我一直在试图调用我getFitness()
方法,它在compareTo()
方法可以使用,但我不断收到此错误无法调用我的方法在数组类型int []
不能对数组类型为int调用getFitness()[]
我不确定这个错误来自哪里。附件将会是提到的方法和构造函数,我将概述出现这种错误的位置。谢谢。
public class Individual implements Comparable<Individual> {
Random rand=new Random(); //Initialize random object
private int size; //Represents N queens
private int[] individual; //Represents the array of possible solutions
public Individual(int[] permutation) {
individual=permutation;
size=individual.length;
}
public Individual(int size) {
this.size=size;
individual=Util.getPermutation(size); //Constructs an individual object that is an array of ints
}
public int getFitness() {
//How many queens are attacking each other on the diagonal
// 0 Represents the best fitness, this is the solution
//Number of possible differences in permutation is found through factorial addition
int newSize=0;
for (int i=0; i<=size; i++){
newSize+=i;
}
int fitness=0;
int [] xDifference=new int[newSize]; //Array that stores distance between Columns
int [] yDifference=new int[newSize]; //Array that stores distance between rows
//Calculates the distance between columns and stores them
for (int i=0; i<size; i++){
for (int j=i+1; j<size; j++)
xDifference[i]=j-i;
}
//Calculates distance between rows and stores them
for (int i=0;i<size;i++){
for (int j=i+1; j<size; j++)
yDifference[i]=Math.abs(individual[j]-individual[i]);
}
//Compares xDifference and yDifference elements, if they are equal that means Queens are attacking
for (int i=0; i<size; i++){
if (xDifference[i]==yDifference[i]){
fitness++;
}
}
return fitness;
}
public int compareTo(Individual other) {
int compare;
if (individual.getFitness()<other.getFitness()){ //ERROR OCCURS HERE
compare=-1;
}else if (individual.getFitness()>other.getFitness()){// ERROR HERE
compare=1;
}else {
compare=0;
}
return compare;
}
}
答
问题是您要求individual.getFitness()
。 individual
确实是int[]
,而不是Individual
对象。相反,你需要使用
if (this.getFitness()<other.getFitness()){
compare=-1;
}
你也可以离开了this.
,但我个人认为它使代码更易于阅读。
答
在你compareTo方法您正在访问的领域individual
这是一个数组,而不是一个Individual
。
'个人'是你的'可能的解决方案'的数组,它是一个'int []'。你想用'this'而不是'individual'。 – EpicPandaForce 2015-02-08 20:16:28