隐藏不同检查比例的不同divs
Got this code in the following question 嗨! 如何将此代码转换为“通用”。目前它只适用于一种情况。如果我有两个它不会工作。隐藏不同检查比例的不同divs
谢谢
$(document).ready(function() {
$('input[type="radio"]').click(function() {
if($(this).attr('id') == 'watch-me') {
$('#show-me').show();
}
else {
$('#show-me').hide();
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div class="medium-12">
<label>Are you a member?</label>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<div id="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
你必须设置一个共同的class
,做DOM遍历相对于所选择的单选按钮。
事情要注意的是:
- 使用更改事件,而不是为单选按钮,单击事件。
- 使用该值来检测单选按钮,而不是嗅探其ID。
$(document).ready(function() {
$('input[type="radio"]').change(function() {
$(this).closest('fieldset').find('.show-me').toggle(this.value == "yes");
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div class="medium-12">
<label>Are you a member?</label>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<div class="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<div class="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<div class="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
@RaRajaprabhu Aravindasamy令人惊叹,完美! 谢谢! – grcoder
注意:如果使用附加到'document'的委托事件处理程序,则不需要DOM就绪处理程序,并且连接到大量元素的效率更高。 –
@GoneCoding代替文档,我们必须使用最近的静态父级来附加委托事件处理程序以获得更多性能。 –
如果我有两个将无法正常工作。
为什么? ::因为如果你只是复制/粘贴相同的结构两次,你将有重复的ID,这是无效的,使你的JS代码无用。
你需要的是基于类名或ATTR像这样的结构:
$(document).ready(function() {
$('input[type="radio"]').click(function() {
if($(this).attr('value') == 'yes') {
$(this).siblings('.show-me').show();
}
else {
$(this).siblings('.show-me').hide();
}
});
});
.show-me {
display:none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div class="medium-12">
<label>Are you a member?</label>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<div class="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me2" value="yes" name="Member2" class="tap-input">
<label for="watch-me2">Yes</label>
<input type="radio" id="MemberNo2" value="no" name="Member2" class="tap-input">
<label for="MemberNo2">No</label>
<div class="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber2">Please enter your Membership number</label>
<input id="memberNumber2" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
谢谢!我正在尝试这样。我应该去上课和价值attr !.很棒 – grcoder
因为你可以做这样的事情不同的值。
function showHide(input){
var attrVal = $(input).attr('id');
switch (attrVal) {
case 'watch-me':
$('#show-me-2').hide();
$('#show-me').show();
break;
case "watch-me-maybe":
$('#show-me').hide();
$('#show-me-2').show();
break;
default :
$('#show-me-2').hide();
$('#show-me').hide();
break;
}
}
$(document).ready(function() {
$('input[type="radio"]').each(function(){
showHide(this);
});
$('input[type="radio"]').click(function() {
showHide(this);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div class="medium-12">
<label>Are you a member?</label>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input" checked="checked">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<input type="radio" id="watch-me-maybe" value="maybe" name="Member" class="tap-input">
<label for="MemberMaybe">Maybe</label>
<div id="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
<div id="show-me-2" class="medium-12">
<div class="form-row">
<label for="memberNumber2">Please enter your Membership number2</label>
<input id="memberNumber2" name="memberNumber2" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
非常感谢。由于其简单性,我选择了RajaprabhuAravindasamy答案。再次谢谢你! – grcoder
我试图使这项工作没有考虑考虑任何class
或id
,只是html
结构。
看到这里jsfiddle
从未使用重复的ID!不要把相同的ID在2个或更多不同的元素,使用类,而不是
使用
attr('value')
找到自己的元素,而不是attr('id')
JQ:
$("fieldset").each(function(){
var showme = $(this).children("div"),
radio = $(this).children('input[type="radio"]')
$(radio).change(function() {
if($(this).attr('value') == 'yes') {
$(showme).show();
}
else {
$(showme).hide();
}
});
});
让我知道,如果它帮助
亲爱的@MihaiT,非常感谢,但我选择了RajaprabhuAravindasamy答案,因为它的简单性。再次谢谢你! – grcoder
我看到了答案。这是一个非常好的。在我的回答中,你可以看到,我没有使用任何'class'或'id'。试图尽可能使其成为'通用':) –
更短的版本给你。它使用附加到文档的委托事件(它始终存在,因此不需要DOM就绪处理程序)。在这个意义上
$(document).on('change', ':radio', function() {
$(this).closest('fieldset').find('.show-me').toggle(this.value == "yes");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div class="medium-12">
<label>Are you a member?</label>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<div class="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<div class="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
<div class="medium-6">
<fieldset class="form-row" id="Member">
<input type="radio" id="watch-me" value="yes" name="Member" class="tap-input">
<label for="watch-me">Yes</label>
<input type="radio" id="MemberNo" value="no" name="Member" class="tap-input">
<label for="MemberNo">No</label>
<div class="show-me" class=" medium-12">
<div class="form-row">
<label for="memberNumber">Please enter your Membership number</label>
<input id="memberNumber" name="memberNumber" class="inputfield" type="text">
</div>
</div>
</fieldset>
</div>
谢谢你。我已经测试过了。我会用它:) – grcoder
使用类名来代替IDS – DaniP
通用:相对缓慢的过滤器表达式(
:radio
)仅在活动时间运行时(没关系)? –什么不起作用? – demo