设置进度,进度条
在活动中,它有一个ListView
其中ListView
项目由3 TextView
(monthAndYear,totalUsed(RM20)和预算(RM123.0)),和ProgressBar
。我尝试了下面的代码来显示ProgressBar
的进度,但没有发生任何事情。设置进度,进度条
public void retrieveList(String name) {
search.clear();
database = mdb.getReadableDatabase();
Cursor cursor = database.rawQuery("SELECT * FROM " + MyDatabaseHelper.TABLE__TASK + " WHERE Name = ? ", new String[]{name}, null);
if (cursor != null && cursor.getCount() > 0) {
while (cursor.moveToNext()) {
int iD = cursor.getInt(cursor.getColumnIndex("ID"));
String month = cursor.getString(cursor.getColumnIndex("Month"));
double budget = cursor.getDouble(cursor.getColumnIndex("Budget"));
double totalUsed=cursor.getDouble(cursor.getColumnIndex("Total_Used"));
if (adapter != null) {
adapter.add(iD,month,budget,totalUsed);
listview.setAdapter(adapter);
}
}
}
}
适配器
public void add(int id,String month,double budget,double used)
{
List obj = new List(id,month,budget,used);
obj.setMonthYear(" " + month);
obj.setBudget(budget);
obj.setUsed(used);
total = budget - used;
obj.setProgress(total);
search.add(obj);
this. notifyDataSetChanged();
}
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder =null;
if (convertView == null) {
convertView = mInflater.inflate(R.layout.expenses_adapter, null);
holder= new ViewHolder();
holder.monthAndYear = (TextView) convertView.findViewById(R.id.monthAndYear);
holder.budget = (TextView) convertView.findViewById(R.id.budget);
holder.amount=(TextView)convertView.findViewById(R.id.amount);
holder.progressBar=(ProgressBar)convertView.findViewById(R.id.downloadProgressBar);
convertView.setTag(holder);
} else {
holder = (ViewHolder) convertView.getTag();
}
holder.monthAndYear.setText(search.get(position).getMonthAndYear());
holder.budget.setText("RM"+""+search.get(position).getBudget());
holder.amount.setText("RM"+""+search.get(position).getUsed());
return convertView;
}
static class ViewHolder {
TextView monthAndYear, budget,amount;
ProgressBar progressBar;
}
后,我holder.amount.setText("RM"+""+search.get(position).getUsed());
之后添加holder.progressBar.setProgress(Integer.parseInt(total+""));
,应用程序崩溃。
错误
java.lang.NumberFormatException: Invalid int: "1.0"
at java.lang.Integer.invalidInt(Integer.java:138)
at java.lang.Integer.parse(Integer.java:375)
at java.lang.Integer.parseInt(Integer.java:366)
at java.lang.Integer.parseInt(Integer.java:332)
at com.example.tony.monthlyexpenses.adapter.ExpensesAdapter.getView(ExpensesAdapter.java:106)
at android.widget.AbsListView.obtainView(AbsListView.java:2232)
holder.progressBar.setProgress(Integer.parseInt(total+""));
此行是给你一个错误。您试图将“1.0”字符串解析为Integer,但值1.0是浮点类型。
请试试这样: 取浮动值并舍入它。这将返回整数
Math.round(Float.parseFloat(total+""))
只要改变:
Integer.parseInt(total+"")
到:
(int) total
,或者,如果你想更精确:
Math.round(total)
你哈已经替换: holder.progressBar.setProgress(Integer.parseInt(total+""));
随着:
holder.progressBar.setProgress(Math.round(total));
值total
要么是double
或float
,所述setProgress()
方法采用int
作为参数。
所以,你可以做到以下几点,改变total
类型的int
,
或使用:
setProgress(Math.round(total));
的Math.round
功能可以通过double
或float
使用,它将再现int
如果您通过float
,或通过double
通过long
。输出将返回将输入四舍五入到最接近的十进制数的值。
他不能直接将字符串转换为int,因为总数是字符串值 –
因为+“” –
我认为它是浮点数或双精度值它实际上是,因为您可以看到total = budget - used,是双打的 –