如何添加JSON支持与XML已经工作?

问题描述:

JSON支持如何添加到dispatch-servlet.xml(XML正在工作没有问题)?
注释文本只是失败的尝试......如何添加JSON支持与XML已经工作?

<?xml version="1.0" encoding="UTF-8"?> 
<beans:beans xmlns="http://www.springframework.org/schema/mvc" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:beans="http://www.springframework.org/schema/beans" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:oxm="http://www.springframework.org/schema/oxm" 
    xsi:schemaLocation=" 
     http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd 
     http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 
     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd 
     http://www.springframework.org/schema/oxm http://www.springframework.org/schema/oxm/spring-oxm-3.0.xsd"> 


    <context:annotation-config/> 
    <context:component-scan base-package="com.example"/> 

    <oxm:jaxb2-marshaller id="marshaller" contextPath="com.example.domain"/> 

    <beans:bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> 
     <beans:property name="messageConverters"> 
      <beans:list> 
       <beans:bean class="org.springframework.http.converter.xml.MarshallingHttpMessageConverter"> 
        <beans:constructor-arg ref="marshaller"/> 
       </beans:bean> 
<!--    <beans:bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"> 
       <beans:constructor-arg ref="marshaller"/> 
       </beans:bean> --> 
      </beans:list> 
     </beans:property> 
    </beans:bean> 

    <beans:bean class="org.springframework.web.servlet.view.BeanNameViewResolver"/> 

    <beans:bean name="note" class="org.springframework.web.servlet.view.xml.MarshallingView"> 
     <beans:constructor-arg ref="marshaller"/> 
    </beans:bean> 
<!-- <beans:bean name="note" class="org.springframework.web.servlet.view.json.MappingJacksonJsonView"> 
    <beans:constructor-arg ref="marshaller"/> 
</beans:bean> --> 

    <!-- InternalResourceViewResolver should be the last sice it always returns/resolves a view --> 
    <beans:bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
     <beans:property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></beans:property> 
     <beans:property name="prefix" value="/WEB-INF/jsp/"></beans:property> 
     <beans:property name="suffix" value=".jsp"></beans:property> 
    </beans:bean> 

</beans:beans> 

其他的解决方案,用于: method=RequestMethod.POST, headers = "content-type=application/json"
你仍然需要:

<beans:bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter> 
    <beans:property name="messageConverters"> 
     <beans:list> 
      <beans:bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter" /> 
     </beans:list> 
    </beans:property> 
</beans:bean> 

要正确绑定的Java对象@RequestBody

+6

哇,有什么用下来票?至少让我指点一下...... – Solata 2010-11-18 17:31:14

+3

不是一个downvoter,但我会想象它是不是告诉我们*失败的尝试失败和错误是什么:) – Affe 2010-11-18 18:00:02

+0

好吧,我同意,我可以去更多在详细... AHungerArtist的答案帮助:) – Solata 2010-11-18 20:37:22

尝试这样:

<bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"> 
     <property name="objectMapper"> 
      <ref bean="JacksonObjectMapper" /> 
     </property> 
</bean> 

<bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView"> 
    <property name="objectMapper"> 
     <ref bean="JacksonObjectMapper" /> 
    </property> 
</bean> 

<bean id="JacksonObjectMapper" class="org.codehaus.jackson.map.ObjectMapper" /> 

它不会让你将使用JAXB编组实例杰克逊感(我不认为)。

使用ContentNegotiatingViewResolver的例子:

<bean 
    class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver"> 
    <property name="mediaTypes"> 
     <map> 
      <entry key="json" value="application/json" /> 
      <entry key="xml" value="application/xml" /> 
     </map> 
    </property> 
    <property name="defaultViews"> 
     <list> 
      <bean 
       class="org.springframework.web.servlet.view.json.MappingJacksonJsonView"> 
       <property name="objectMapper"> 
        <ref bean="JacksonObjectMapper" /> 
       </property> 
      </bean> 
      <bean class="org.springframework.web.servlet.view.xml.MarshallingView"> 
       <property name="marshaller"> 
        <ref bean="Jaxb2Marshaller" /> 
       </property> 
      </bean> 
     </list> 
    </property> 
    <property name="favorPathExtension" value="false" /> 
    <property name="favorParameter" value="true" /> 
    <property name="useNotAcceptableStatusCode" value="true" /> 
</bean> 
+0

你明白了,但如果我离开XML豆出来的作品。你能否建议如何结合XML使用它,并为BeanNameViewResolver使用相同的“ Solata 2010-11-18 20:42:55

+0

你在和哪个版本的Spring合作?以及你如何/在哪里使用笔记? – AHungerArtist 2010-11-18 20:55:54

+0

如果您可以使用ContentNegotiatingViewResolver,那么弹出并使用它似乎很容易。 – AHungerArtist 2010-11-18 21:11:52

我发现在这里,你可能需要更新您的杰克逊 - 翔升罐子版http://forum.springsource.org/showthread.php?t=83954

试着看那个,看是否将其升级解决了这个问题。

+0

如果这只是Glassfish ...我使用Jetty,也尝试添加杰克逊所有1.6.2.jar与相同的错误。 AHungerArtist得到了它。 – Solata 2010-11-18 20:52:34

+0

嘿,感谢您更新我的文章,所以我可以看到答案:-) – wajiw 2010-11-18 20:55:08