SQL - SQLite的计数连续编号

Question

我有下列数据的表：

id | numbers | date 
---------------------------------- 
1 | -1-4-6- | 2009-10-26 15:30:20 
2 | -1-4-7- | 2009-10-26 16:45:10 
3 | -4-5-8- | 2009-10-27 11:21:34 
4 | -2-6-7- | 2009-10-27 13:12:56 
5 | -1-3-4- | 2009-10-28 14:22:14 
6 | -1-2-4- | 2009-10-29 20:28:16 
. . ....... . ................... 

在这个例子表我用一个like查询统计的数字，例如：

select count(*) from table where numbers like '%-4-%' 
Result: 5 

现在，如何我可以计算（使用像）一个数字连续出现多少次（在这种情况下是数字4）？ 我的意思是：4号连续出现在ID 1,2,3和5,6，所以我想有结果的查询：2

Answer 1

这应该这样做。

create table "table" (id int, numbers text); 
insert into "table" values (1, '-1-4-6-'); 
insert into "table" values (2, '-1-4-7-'); 
insert into "table" values (3, '-4-5-8-'); 
insert into "table" values (4, '-2-6-7-'); 
insert into "table" values (5, '-1-3-4-'); 
insert into "table" values (6, '-1-2-4-'); 

SELECT count(*) 
FROM (
    SELECT "table".*, temp1.id, temp2.id 
    FROM "table" 
    INNER JOIN "table" temp1 
     ON "table".id = temp1.id+1 
    LEFT JOIN (
     SELECT id FROM "table" WHERE numbers LIKE '%-4-%' 
    ) temp2 ON temp1.id+1 = temp2.id+2 

    WHERE "table".numbers LIKE '%-4-%' 
     AND "temp1".numbers LIKE '%-4-%' 
     AND temp2.id IS NULL 
) consecutive_groups_gt_1 

[编辑：添加测试数据和纠正报价]

[编辑：更改的查询只只能算哪里有行组至少有2名成员]