SQL的错误信息 - 附近有语法错误）“

问题描述：

”附近有语法错误）'。“

从sum(PayHours)行，我将不胜感激关于如何去解决它的一些指导。我被卡住了。

[#PremierThree]从下面的代码是在运行中所创建的临时表和事后

SELECT * 
FROM [#PremierThree] 
PIVOT 
    (SUM(PayHours) 
    FOR [Pay_ClassHrs] IN ([PBS_Hrs], [POT_Hrs], [PED_Hrs], [POR_Hrs], [Agency_Hrs], [PWH_Hrs], [Sick_Hrs], [PTO_Hrs], [Holiday_Hrs], [PJB_Hrs], [Bugeted_Work_Hrs], [Bugeted_Benefit_Hrs]) 
    ) AS pvt1 
PIVOT 
    (SUM(PayAmount) 
    FOR [Pay_Class$] in ([PBS_$], [POT_$], [PED_$], [POR_$], [Agency_$], [PWH_$], [Sick_$], [PTO_$], [Holiday_$], [PJB_$], [PNH_$],[Bugeted_Work_$], [Bugeted_Benefit_$]) 
    ) AS pvt2 
ORDER BY 
    [Facility], CAST([Job_Code] AS INT)

你的父母很明显是不平衡的。））为pvt1 ...为什么两个密切的parens只有一个开放paren？ – pmbAustin

为我成功编译 – Artem

你不需要所有的方括号，他们只是使这很难阅读。 –

答

下降枢轴查询不包含在T-SQL 2项或多个枢纽条款看FROM - Using PIVOT and UNPIVOT

你是试图输出小时和美元作为“2列集”，并坦率地说，我发现T-SQL实现的主要限制。您可以尝试使用unpivot并一起旋转以获得所需效果（example here）。我个人会选择一种更传统的数据透视查询方式，根据需要简单地使用GROUP BY和case expressions（我们总是在“透视图被添加到SQL之前必须使用的样式）。eg（但是我离开列别名由你）

SELECT 
     [Facility] 
    , [Job_Code] 

    , SUM(CASE WHEN Pay_ClassHrs = 'PBS_Hrs' THEN Pay_ClassHrs END)    AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'POT_Hrs' THEN Pay_ClassHrs END)    AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'PED_Hrs' THEN Pay_ClassHrs END)    AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'POR_Hrs' THEN Pay_ClassHrs END)    AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'Agency_Hrs' THEN Pay_ClassHrs END)   AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'PWH_Hrs' THEN Pay_ClassHrs END)    AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'Sick_Hrs' THEN Pay_ClassHrs END)   AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'PTO_Hrs' THEN Pay_ClassHrs END)    AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'Holiday_Hrs' THEN Pay_ClassHrs END)   AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'PJB_Hrs' THEN Pay_ClassHrs END)    AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'Bugeted_Work_Hrs' THEN Pay_ClassHrs END) AS x 
    , SUM(CASE WHEN Pay_ClassHrs = 'Bugeted_Benefit_Hrs' THEN Pay_ClassHrs END) AS x 

    , SUM(CASE WHEN Pay_Class$ = 'POT_$' THEN Pay_Class$ END)     AS x 
    , SUM(CASE WHEN Pay_Class$ = 'PED_$' THEN Pay_Class$ END)     AS x 
    , SUM(CASE WHEN Pay_Class$ = 'POR_$' THEN Pay_Class$ END)     AS x 
    , SUM(CASE WHEN Pay_Class$ = 'Agency_$' THEN Pay_Class$ END)    AS x 
    , SUM(CASE WHEN Pay_Class$ = 'PWH_$' THEN Pay_Class$ END)     AS x 
    , SUM(CASE WHEN Pay_Class$ = 'Sick_$' THEN Pay_Class$ END)     AS x 
    , SUM(CASE WHEN Pay_Class$ = 'PTO_$' THEN Pay_Class$ END)     AS x 
    , SUM(CASE WHEN Pay_Class$ = 'Holiday_$' THEN Pay_Class$ END)    AS x 
    , SUM(CASE WHEN Pay_Class$ = 'PJB_$' THEN Pay_Class$ END)     AS x 
    , SUM(CASE WHEN Pay_Class$ = 'PNH_$' THEN Pay_Class$ END)     AS x 
    , SUM(CASE WHEN Pay_Class$ = 'Bugeted_Work_$' THEN Pay_Class$ END)   AS x 
    , SUM(CASE WHEN Pay_Class$ = 'Bugeted_Benefit_$' THEN Pay_Class$ END)  AS x 

FROM [#PremierThree] 
GROUP BY 
     [Facility] 
    , [Job_Code]

UNTESTED！

如果上面的方法看起来太旧帽子，罗嗦你。尝试使用加入结合2个枢轴，下面我甲肝e假设它需要一个full outer join，但如果两个子查询产生相同的行（，很可能在您的情况下使用该临时表），它可能会与更简单的inner join一起使用。

SELECT 
     COALESCE(p1.Facility,p2.Facility) Facility 
    , COALESCE(p1.Job_Code,p2.Job_Code) Job_Code 
    , [PBS_Hrs], [POT_Hrs], [PED_Hrs], [POR_Hrs], [Agency_Hrs], [PWH_Hrs], [Sick_Hrs], [PTO_Hrs], [Holiday_Hrs], [PJB_Hrs], [Bugeted_Work_Hrs], [Bugeted_Benefit_Hrs] 
    , [PBS_$], [POT_$], [PED_$], [POR_$], [Agency_$], [PWH_$], [Sick_$], [PTO_$], [Holiday_$], [PJB_$], [PNH_$],[Bugeted_Work_$], [Bugeted_Benefit_$] 
FROM (
     SELECT 
      [Facility] 
      , [Job_Code] 
      , [PBS_Hrs], [POT_Hrs], [PED_Hrs], [POR_Hrs], [Agency_Hrs], [PWH_Hrs], [Sick_Hrs], [PTO_Hrs], [Holiday_Hrs], [PJB_Hrs], [Bugeted_Work_Hrs], [Bugeted_Benefit_Hrs] 
     FROM [#PremierThree] 
     PIVOT 
      (SUM(PayHours) 
      FOR [Pay_ClassHrs] IN ([PBS_Hrs], [POT_Hrs], [PED_Hrs], [POR_Hrs], [Agency_Hrs], [PWH_Hrs], [Sick_Hrs], [PTO_Hrs], [Holiday_Hrs], [PJB_Hrs], [Bugeted_Work_Hrs], [Bugeted_Benefit_Hrs]) 
     ) AS pvt1 
    ) AS p1 
FULL OUTER JOIN (
     SELECT 
      [Facility] 
      , [Job_Code] 
      , [PBS_$], [POT_$], [PED_$], [POR_$], [Agency_$], [PWH_$], [Sick_$], [PTO_$], [Holiday_$], [PJB_$], [PNH_$],[Bugeted_Work_$], [Bugeted_Benefit_$] 
     PIVOT 
      (SUM(PayAmount) 
      FOR [Pay_Class$] in ([PBS_$], [POT_$], [PED_$], [POR_$], [Agency_$], [PWH_$], [Sick_$], [PTO_$], [Holiday_$], [PJB_$], [PNH_$],[Bugeted_Work_$], [Bugeted_Benefit_$]) 
     ) AS pvt2 
    ) AS p2 
      ON p1.Facility = p2.Facility AND p1.Job_Code = p2.Job_Code 
ORDER BY 
    [Facility], CAST([Job_Code] AS INT) 
;

对于T-SQL：就个人而言，即使使用连接方法，在开始变得复杂时我也没有看到使用pivot的好处。

SQL的错误信息 - 附近有语法错误）“

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