Python列表对象属性'append'是只读的

Question

正如标题所说，在python中，我试图让某人在某个选择中输入（在这种情况下为Choice13），然后它将旧密码从列出密码并添加新密码。

passwords = ['mrjoebblock' , 'mrjoefblock' , 'mrjoegblock', 'mrmjoeadmin' ] 
if choice == '3': 
    password = raw_input('Welcome admin! I\'m going to need your password ') 
     if password == 'mrjoeadmin': 
      print('Welcome Mr. Joe!') 
      Choice11 = raw_input('What would you like to do? Press 1 for changing your admin password, 2 for viewing a class\'s comments, or 3 for changing a class\'s password') 
      if Choice11 == '1': 
       print('You have chosen to change your password! ') 
       Choice12 = raw_input('You will need to put in your current password to access this feature ') 
       if Choice12 == 'mrmajoeadmin': 
        Choice13 = raw_input('What would you like to change your password to? ') 
        passwords.remove('mrjoeadmin') 
        passwords.append = Choice13 

Answer 1

要追加东西的清单，你需要呼叫的append方法：

passwords.append(Choice13) 

正如你所看到的，在一个例外，你分配到 append方法结果不应该替换内建对象的方法 - （如果你想修改内建类型，支持的方式是通过子类化）。

Answer 2

，或者你可以做修改同一个列表插槽：

passwords[passwords.index('mrjoeadmin')] = Choice13