用于C++的颜色地图库，可将给定值转换为红色，绿色和蓝色值

Question

我正在寻找将给定值转换为红色，绿色和蓝色值的颜色地图库。类似于matlab的色彩映射功能[1]。最好在C++中。

[1] http://www.mathworks.com/help/techdoc/ref/colormap.html

Answer 1

在想这个的方式，对于库太简单了个人而言，我已经实现了它我的自我他们在C的例子（你可以看一下维基百科的解释数学）：

/** 
    * Computes the color gradiant 
    * color: the output vector 
    * x: the gradiant (beetween 0 and 360) 
    * min and max: variation of the RGB channels (Move3D 0 -> 1) 
    */ 
    void GroundColorMix(double* color, double x, double min, double max) 
{ 
    /* 
    * Red = 0 
    * Green = 1 
    * Blue = 2 
    */ 
    double posSlope = (max-min)/60; 
    double negSlope = (min-max)/60; 

    if(x < 60) 
    { 
     color[0] = max; 
     color[1] = posSlope*x+min; 
     color[2] = min; 
     return; 
    } 
    else if (x < 120) 
    { 
     color[0] = negSlope*x+2*max+min; 
     color[1] = max; 
     color[2] = min; 
     return; 
    } 
    else if (x < 180 ) 
    { 
     color[0] = min; 
     color[1] = max; 
     color[2] = posSlope*x-2*max+min; 
     return; 
    } 
    else if (x < 240 ) 
    { 
     color[0] = min; 
     color[1] = negSlope*x+4*max+min; 
     color[2] = max; 
     return; 
    } 
    else if (x < 300 ) 
    { 
     color[0] = posSlope*x-4*max+min; 
     color[1] = min; 
     color[2] = max; 
     return; 
    } 
    else 
    { 
     color[0] = max; 
     color[1] = min; 
     color[2] = negSlope*x+6*max; 
     return; 
    } 
}