学习C#从俄罗斯方块开始(三)俄罗斯方块的优化和美化
前两节地址：
按照我们第一节课程《学习C#从俄罗斯方块开始(一)概述》的规划。我们在完成了俄罗斯方块Demo后，我们将要对Demo进行优化和美化设置，使得俄罗斯的可玩性增强。本节课程我们就从算法的优化、游戏的美化和可玩性的扩展性上进行改进，让我们的游戏变得强大起来，也让我们的开发技术上一个小小的台阶。
第一、算法的优化：
在Demo中，我们基本上都是用循环来完成向下、向左、向右的移动、检查是否存在可以得分的行等动作。在这些循环中我们使用了从0到最大值的循环。本算法的优化，我们主要着重于缩小循环的范围开始。经过我们的观察发现。在检测是否满行和绘制背景的时候，我们采用了历边所有的背景数组。我们可以缩小到只在俄罗斯方块完成落下的最小高度上进行检测，这样就大大的缩小了我们的循环范围。
所以我们申明了一个参数：lowY.
private int lowY = 19; //初始化的时候为到最下面。然后随着lowY的增加，循环范围会原来越大
原来我们的检测是否得分的函数：
private void CheckSore() { for (int y = 19; y > -1; y--) { bool isFull = true; for (int x = 13; x > -1; x--) { if (bgGraoud[y, x] == 0) { isFull = false; break; } } if (isFull) { //增加积分 Sorce = Sorce + 100; for (int yy = y; yy > 0; yy--) { for (int xx = 0; xx < 14; xx++) { int temp = bgGraoud[yy - 1, xx]; bgGraoud[yy, xx] = temp; } } y++; label1.Text = Sorce.ToString(); ; Draw(); } } }
就可以优化为：
private void CheckSore() { for (int y = 19; y > lowY; y--) { bool isFull = true; for (int x = 13; x > -1; x--) { if (bgGraoud[y, x] == 0) { isFull = false; break; } } if (isFull) { //增加积分 lowY++; //减少了一行，循环就可以减少一行 Sorce = Sorce + 100; for (int yy = y; yy > 0; yy--) { for (int xx = 0; xx < 14; xx++) { int temp = bgGraoud[yy - 1, xx]; bgGraoud[yy, xx] = temp; } } y++; label1.Text = Sorce.ToString(); ; Draw(); } } }
原来的绘图函数
private void Draw() { Graphics g = Graphics.FromImage(myImage); g.Clear(this.BackColor); for (int bgy = 0; bgy < 20; bgy++) { for (int bgx = 0; bgx < 14; bgx++) { if (bgGraoud[bgy, bgx] == 1) { g.FillRectangle(new SolidBrush(Color.Blue), bgx * 20, bgy * 20, 20, 20); } } } //绘制当前的图片 for (int y = 0; y < 4; y++) { for (int x = 0; x < 4; x++) { if (CurrentTrick[y, x] == 1) { g.FillRectangle(new SolidBrush(Color.Blue), (x + CurrentX) * 20, (y + CurrentY) * 20, 20, 20); } } } Graphics gg = panel1.CreateGraphics(); gg.DrawImage(myImage, 0, 0); }
则可以优化为：
private void Draw() { Graphics g = Graphics.FromImage(myImage); g.Clear(this.BackColor); for (int bgy = lowY; bgy < 20; bgy++) { for (int bgx = 0; bgx < 14; bgx++) { if (bgGraoud[bgy, bgx] == 1) { g.FillRectangle(new SolidBrush(Color.Blue), bgx * 20, bgy * 20, 20, 20); } } } //绘制当前的图片 for (int y = 0; y < 4; y++) { for (int x = 0; x < 4; x++) { if (CurrentTrick[y, x] == 1) { g.FillRectangle(new SolidBrush(Color.Blue), (x + CurrentX) * 20, (y + CurrentY) * 20, 20, 20); } } } Graphics gg = panel1.CreateGraphics(); gg.DrawImage(myImage, 0, 0); }
关于游戏的美化：
我们着重美化了游戏的砖块，把蓝色的惨不忍睹的砖块，变成多个颜色，仿三维样式的方块。效果图如下
在这里因为需要变成不同的颜色，所以背景必须有以前的x,y轴的两维信息，变成一个x,y的数字 和 color的三维信息。所以背景数组变化为：
#region 定义背景 private int[,,] bgGraoud ={ {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, {{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0},{0,0}}, }; #endregion
同时我们定义了一个TricksColor的颜色数组，每个砖块对照三个颜色信息，分别表示显示出来的三个面的颜色：（具体的颜色各位可以再自己的游戏中随便变换，以达到美观为目的.)
private Color[,] TricksColor = { {Color.FromArgb(0,0,255),Color.FromArgb(200,200,253),Color.FromArgb(98,98,140)}, {Color.FromArgb(255,255,0),Color.FromArgb(253,253,200),Color.FromArgb(189,189,84)}, {Color.FromArgb(0,0,255),Color.FromArgb(200,200,253),Color.FromArgb(98,98,140)}, {Color.FromArgb(255,255,0),Color.FromArgb(253,253,200),Color.FromArgb(189,189,84)} };
因为背景数组发生了变化，所以我们的当前砖块也相应的变成了三维数组，代码都随之改动。现在我们主要贴出来draw的变化，关于其他代码的变化。大家可以去源文件中查看详细的注释：
private void Draw() { Graphics g = Graphics.FromImage(myImage); g.Clear(panel1.BackColor); for (int bgy = 19; bgy > lowY - 1; bgy--) { for (int bgx = 0; bgx < 14; bgx++) { if (bgGraoud[bgy, bgx, 0] == 1) { //首先我们绘制一个框 g.FillRectangle(new SolidBrush(TricksColor[bgGraoud[bgy, bgx, 1], 0]), bgx * 20, bgy * 20, 20, 20); //绘制上边 g.DrawRectangle(new Pen(panel1.BackColor), bgx * 20, bgy * 20, 20, 20); Point[] myPoints1 = { new Point(bgx * 20 + 5, bgy * 20 - 5), new Point(bgx * 20 + 25, bgy * 20 - 5), new Point(bgx * 20 + 20, bgy * 20), new Point(bgx * 20, bgy * 20) }; g.FillPolygon(new SolidBrush(TricksColor[bgGraoud[bgy, bgx, 1], 1]), myPoints1); g.DrawPolygon(new Pen(panel1.BackColor), myPoints1); //绘制右边 Point[] myPoints2 = { new Point(bgx * 20 + 20, bgy*20), new Point(bgx * 20 + 25, bgy * 20 - 5), new Point(bgx * 20 + 25, bgy * 20 + 15), new Point(bgx * 20 + 20, bgy * 20 + 20) }; g.FillPolygon(new SolidBrush(TricksColor[bgGraoud[bgy, bgx, 1], 2]), myPoints2); } } } //绘制当前的图片 for (int y = 3; y >= 0; y--) { for (int x = 0; x < 4; x++) { if (CurrentTrick[y, x,0] == 1) { g.FillRectangle(new SolidBrush(TricksColor[CurrentTrick[y,x,1], 0]), (x + CurrentX) * 20, (y + CurrentY) * 20, 20, 20); g.DrawRectangle(new Pen(panel1.BackColor), (x + CurrentX) * 20, (y + CurrentY) * 20, 20, 20); //绘制上边 //绘制右边 if (x + 1 + CurrentX < 14) { if (bgGraoud[y + CurrentY, x + 1 + CurrentX, 0] == 0) { Point[] myPoints1 = { new Point((x + CurrentX) * 20 + 5, (y + CurrentY) * 20 - 5), new Point((x + CurrentX) * 20 + 25, (y + CurrentY) * 20 - 5), new Point((x + CurrentX) * 20 + 20, (y + CurrentY) * 20), new Point((x + CurrentX) * 20, (y + CurrentY) * 20) }; g.FillPolygon(new SolidBrush(TricksColor[CurrentTrick[y, x, 1], 1]), myPoints1); g.DrawPolygon(new Pen(panel1.BackColor), myPoints1); Point[] myPoints2 = { new Point((x + CurrentX) * 20 + 20, (y + CurrentY) * 20), new Point((x + CurrentX) * 20 + 25, (y + CurrentY) * 20 - 5), new Point((x + CurrentX) * 20 + 25, (y + CurrentY) * 20 + 15), new Point((x + CurrentX) * 20 + 20, (y + CurrentY) * 20 + 20) }; g.FillPolygon(new SolidBrush(TricksColor[CurrentTrick[y, x, 1], 2]), myPoints2); } else { Point[] myPoints1 = { new Point((x + CurrentX) * 20 + 5, (y + CurrentY) * 20 - 5), new Point((x + CurrentX) * 20 + 20, (y + CurrentY) * 20 - 5), new Point((x + CurrentX) * 20 + 20, (y + CurrentY) * 20), new Point((x + CurrentX) * 20, (y + CurrentY) * 20) }; g.FillPolygon(new SolidBrush(TricksColor[CurrentTrick[y, x, 1], 1]), myPoints1); g.DrawPolygon(new Pen(panel1.BackColor), myPoints1); } } else { Point[] myPoints1 = { new Point((x + CurrentX) * 20 + 5, (y + CurrentY) * 20 - 5), new Point((x + CurrentX) * 20 + 20, (y + CurrentY) * 20 - 5), new Point((x + CurrentX) * 20 + 20, (y + CurrentY) * 20), new Point((x + CurrentX) * 20, (y + CurrentY) * 20) }; g.FillPolygon(new SolidBrush(TricksColor[CurrentTrick[y, x, 1], 1]), myPoints1); g.DrawPolygon(new Pen(panel1.BackColor), myPoints1); } } } } Graphics gg = panel1.CreateGraphics(); gg.DrawImage(myImage, 0, 0); }
关于绘图的代码其实也很容易理解，我们首先通过在原来图片的基础上在斜上方和斜右进行绘制，使得大家看起来像三维的砖块了。另外在绘制砖块的时候，采用了对背景判断，已经砖块衍生出来的色块会覆盖背景。
可玩性的优化：
首先，我们针对我们的游戏进行了关卡设置。我们使得游戏每增加1000分。游戏进入一关。没进入一关，速度都变快.用技术的语言讲：每进入一关，把timer的时间间隔缩小一部分即可。
private int Step = 1; //我们首先来申明个关卡的变量。
CheckSorce的函数相应的改变为：
/// <summary> /// 检测是否应该得分，可以优化 /// </summary> private void CheckSore() { for (int y = 19; y > lowY; y--) { bool isFull = true; for (int x = 13; x > -1; x--) { if (bgGraoud[y, x,0] == 0) { isFull = false; break; } } if (isFull) { //增加积分 lowY++; //减少了一行，循环就可以减少一行 Sorce = Sorce + 100; Step = Sorce / 1000 + 1; if (Step == 11) { timer1.Stop(); MessageBox.Show("恭喜恭喜，你的游戏过通关了"); } else { timer1.Interval = (11 - Step) * 100; for (int yy = y; yy > 0; yy--) { for (int xx = 0; xx < 14; xx++) { int temp = bgGraoud[yy - 1, xx, 0]; int temp2 = bgGraoud[yy - 1, xx, 1]; bgGraoud[yy, xx, 0] = temp; bgGraoud[yy, xx, 1] = temp2; } } y++; } label1.Text = "您现在的分数为："+Sorce.ToString(); label1.Text += "/r/n您现在在:"; label1.Text += Step.ToString(); label1.Text += "关"; Draw(); } } }
其次，我们可以增加砖块的种类来优化游戏性：在这里只需要增加砖块数组和颜色数组的元素即可。
具体的可以看源码：俄罗斯方块.rar
此外如果你对这个游戏有任何问题，或者有任何建议，欢迎去csdn论坛一起讨论：
http://topic.csdn.net/u/20100218/15/d5c8a93f-5690-4efb-841e-5a290e7c183e.html
如果你在看这篇文章的话。你可以继续看看这个
http://blog.csdn.net/aofengdaxia/archive/2010/10/15/5944193.aspx