c语言-10进制字符串转16进制字符串
代码1-动态分配:
#include <stdio.h>
#include <string.h>
#include <malloc.h>
char *DecToHex(char *pHex,char *pDec,int Declen)
{
int i,Hexlen = Declen *2;
char hex[] = "0123456789";
pHex = (char *)malloc(sizeof(char)*Hexlen);
for (i = 0; i < Declen; i++)
{
*pHex++ = hex[*pDec>>4];
*pHex++ = hex[*pDec++ & 0x0F];
}
*pHex = '\0';
return pHex -Hexlen;
}
int main()
{
char Dec[] = "01234";
char *pHex = NULL;
printf("-------------10进制字符串----------\n");
printf("%s\n",Dec);
printf("-------------16进制字符串----------\n");
printf("%s\n", DecToHex(pHex,Dec,strlen(Dec)));
printf("\n\n\n");
}
代码2-非动态分配:
#include <stdio.h>
#include <string.h>
#include <malloc.h>
char *DecToHex(char *pHex,char *pDec,int Declen)
{
int i,Hexlen = Declen *2;
char hex[] = "0123456789";
for (i = 0; i < Declen; i++)
{
*pHex++ = hex[*pDec>>4];
*pHex++ = hex[*pDec++ & 0x0F];
}
*pHex = '\0';
return pHex -Hexlen;
}
int main()
{
char Dec[] = "01234";
char Hex[11];
printf("-------------10进制字符串----------\n");
printf("%s\n",Dec);
printf("-------------16进制字符串----------\n");
printf("%s\n", DecToHex(Hex,Dec,strlen(Dec)));
printf("\n\n\n");
}
当然,如果你想完成Ascii码到Hex的转换,只需要将hex[]="0123456789"改成,hex[]="0123456789ABCDEF"。这也是为什么上面没做保护性判断,因为这个函数主要就是完成Ascii到Hex的转换,只是在这里是一种更特殊的情况。
运行结果: