确定如果数值通过If语句超出范围

Question

我正在尝试在bash中构造一个动态IF语句，以确定某个数字是否在预定义范围内或其外部。

some.file

-11.6 

bash代码：的 “可接受的范围内值”

check=`cat some.file` 

if [ ${check} -le "-7.0" ] && [ ${check} -ge "7.0" ]; 
then 
echo "CAUTION: Value outside acceptable range" 
else 
echo "Value within acceptable range" 
fi 

现在，我得到回报的时候显然，-11.6小于-7.0因此超出了范围。

Answer 1

试试这个 -

$ cat f 
2 
$ awk '{if($1 >= -7.0 && $1 <= 7.0) {print "Value within acceptable range"} else {print "CAUTION: Value outside acceptable range"}}' f 
Value within acceptable range 

$ cat f 
-11.6 
$ awk '{if($1 >= -7.0 && $1 <= 7.0) {print "Value within acceptable range"} else {print "CAUTION: Value outside acceptable range"}}' f 
CAUTION: Value outside acceptable range 

OR

$ cat kk.sh 
while IFS= read -r line 
do 
if [ $line -ge -7.0 ] && [ $line -le 7.0 ]; then 
echo "Value within acceptable range" 
else 
echo "CAUTION: Value outside acceptable range" 
fi 
done < f 

处理...

$ cat f 
2 
$ ./kk.sh 
Value within acceptable range 

---

$ cat f 
-11.2 
$ ./kk.sh 
CAUTION: Value outside acceptable range