Java/350. Intersection of Two Arrays II 两个数组的交集 II
题目
代码部分一(4ms 85.80%)
class Solution {
public int[] intersect(int[] nums1, int[] nums2) {
List<Integer> list = new ArrayList<>();
Map<Integer, Integer> map = new HashMap<>();
for(int i = 0; i < nums1.length; i++){
map.put(nums1[i], map.getOrDefault(nums1[i], 0)+1);
}
for(int i = 0; i < nums2.length; i++){
if(map.containsKey(nums2[i])){
if(map.get(nums2[i]) > 0){
list.add(nums2[i]);
map.put(nums2[i], map.get(nums2[i]) - 1);
}
}
}
int[] res = new int[list.size()];
for(int i = 0; i < res.length; i++){
res[i] = list.get(i);
}
return res;
}
}
代码部分二(4ms 85.80%)
class Solution {
public int[] intersect(int[] nums1, int[] nums2) {
int len1 = nums1.length;
int len2 = nums2.length;
int len3 = len1 > len2 ? len1 : len2;
int[] res = new int[len3];
Arrays.sort(nums1);
Arrays.sort(nums2);
int i = 0;
int j = 0;
int k = 0;
while(i < len1 && j < len2){
if(nums1[i] == nums2[j]){
res[k] = nums1[i];
k++;
i++;
j++;
}else
if(nums1[i] < nums2[j]){
i++;
}else{
j++;
}
}
return Arrays.copyOfRange(res, 0, k);
}
}
代码部分三(2ms 99.99%)
class Solution {
public int[] intersect(int[] nums1, int[] nums2) {
int len1 = nums1.length;
int len2 = nums2.length;
Arrays.sort(nums1);
Arrays.sort(nums2);
int i = 0;
int j = 0;
int k = 0;
while(i < len1 && j < len2){
if(nums1[i] == nums2[j]){
nums1[k] = nums2[j];
k++;
i++;
j++;
}else
if(nums1[i] < nums2[j]){
i++;
}else{
j++;
}
}
int[] res = new int[k];
for(int x = 0; x < k; x++){
res[x] = nums1[x];
}
return res;
}
}