Token解密出错:The string "此处为乱码'' doesn't have a valid JSON format(已解决)

最近在毕设里面使用token做登录授权,使用postman测试出现了乱码报错:

com.auth0.jwt.exceptions.JWTDecodeException: The string ‘�z��’G�#�KaTeX parse error: Expected 'EOF', got '&' at position 6: �uB"�&̲�r#��3S"’’ doesn’t have a valid JSON format.

因为这个错误拖了几天的进度
Token解密出错:The string "此处为乱码'' doesn't have a valid JSON format(已解决)

使用postman带token值测试接口我是采用以下方式:
Token解密出错:The string "此处为乱码'' doesn't have a valid JSON format(已解决)

断点发现原来是因为获得token值的时候前面多了Bearer空格,导致我的token值解密成了乱码,如下图:

Token解密出错:The string "此处为乱码'' doesn't have a valid JSON format(已解决)

Token解密出错:The string "此处为乱码'' doesn't have a valid JSON format(已解决)
Token解密出错:The string "此处为乱码'' doesn't have a valid JSON format(已解决)

于是我在获取token时只截取Bearer空格后面的值就解决这个问题啦:

Token解密出错:The string "此处为乱码'' doesn't have a valid JSON format(已解决)