layui-v2.5.6 表头本地存储记忆功能
网上很多都是低版本layui的做法,以下是2.5.6版本的,本人亲测有效,修改modules文件夹下的table.js文件
1、找到F.prototype.events = function () { var e, i = this, a = i.config, o = t("body"), c = {}, s = i.layHeader.find("th"), h = ".layui-table-cell", p = a.elem.attr("lay-filter");这一块代码,再下面加上以下代码:
var tableFlag = window.location.pathname.replace(new RegExp('/', 'g'), "_"); if (typeof tableFlag !== "undefined" && tableFlag != "") { var deploy = localStorage.getItem("TableHidden" + tableFlag + ""); if(deploy != null){ var arr = new Boolean(deploy) ? eval(deploy) : []; $.each(arr, function (index, ele) { var checked = ele.check; var key = ele.key; var parentKey = ele.parentKey; layui.each(a.cols, function (i1, item1) { layui.each(item1, function (i2, item2) { if (i1 + '-' + i2 === key) { var hide = item2.hide; //同步勾选列的hide值和隐藏样式 item2.hide = !checked; i.elem.find('*[data-key="' + i.index + '-' + key + '"]')[checked ? 'removeClass' : 'addClass'](f); //根据列的显示隐藏,同步多级表头的父级相关属性值 // if (hide != item2.hide) { // a.setParentCol(!checked, parentKey); // } //重新适配尺寸 i.resize(); } }) }) }) } }
注:tableFlag也可以每个页面单独定义,我这为了每个页面都能直接用就用路由来处理了
2、紧接着下面几行找到 n.on("checkbox(LAY_TABLE_TOOL_COLS)", function (e) {, 增加以下代码:
if (typeof tableFlag !== "undefined" && tableFlag != "") { var tableHidden = ""; $('.layui-unselect.layui-form-checkbox').each(function (index, ele) { var key = $(ele).siblings('input').attr('data-key'); var parentkey = $(ele).siblings('input').attr('data-parentkey'); var checked = $(ele).attr('class').indexOf('layui-form-checked') !== -1 ? true : false; tableHidden += "{'key':'" + key + "','check':" + checked + ",'parentKey':" + (parentkey ? parentkey : "''") + "},"; }) localStorage.setItem("TableHidden" + tableFlag + "", "[" + tableHidden + "]"); //end }
至此就ok了,勾选某个table中的某几列隐藏,之后再打开这个页面发下之前隐藏的列被隐藏了,实现记忆功能