获取日期范围之间的时间间隔

问题描述：

请有人可以帮助我在这里，我试图得到日期范围之间的小时间隔表。获取日期范围之间的时间间隔

例如：

if starttime == 2012-02-06 23:59:00' 
then endtime = '2012-02-29 10:26:17'

我应该有一个表（变量表）有这样的内容：

Start     End      Seconds 
2012-02-06 23:59:00.000 2012-02-06 23:59:00.000 0 
2012-02-29 09:00:00.000 2012-02-29 09:59:00.000 3540 
2012-02-29 10:00:00.000 2012-02-29 10:26:17.000 1577

纠正我，如果我错了 - 小时列似乎是错误的我。在两种情况下都应该为零。 – 2012-07-13 10:24:46

请检查更新 – 2012-07-13 10:40:59

请检查@LolCoder的答案。 – 2012-07-13 10:41:41

答

谢谢大家的建议和意见。我终于得到了一个是解决可能的问题。

下面是脚本的解决方案，我想出了：

DECLARE @start_date datetime = CONVERT(DATETIME,'2012-02-06 23:59:01.000',20); 
DECLARE @end_date datetime = CONVERT(DATETIME,'2012-12-08 23:59:17.000',20); 
DECLARE @org datetime ; 
DECLARE @end datetime ; 
DECLARE @datetable TABLE (h_start datetime, h_end datetime,h_sesc int); 

WHILE (dateadd(second, -1, dateadd(hour, datediff(hour, 0, @start_date)+1, 0))) < @end_date 
BEGIN 
SET @org = null; 
SET @org = @start_date; 
SET @end = (dateadd(second, -1, dateadd(hour, datediff(hour, 0, @org)+1, 0))); 
INSERT INTO @datetable (h_start, h_end,h_sesc) 
VALUES(dateadd(second, 0,@org), @end,DATEDIFF(second, @org,@end)); 

SET @start_date = dateadd(second, 1,@end); 

END; 


INSERT INTO @datetable (h_start, h_end,h_sesc) 
VALUES(dateadd(second, 0,@start_date), @end_date,DATEDIFF(second, dateadd(second, 0,@start_date),@end_date)); 

SELECT * FROM @datetable;

以上将给出如下因素的结果：

h_start     h_end     h_sesc 
2012-02-06 23:59:01.000 2012-02-06 23:59:59.000 58 
2012-02-07 00:00:00.000 2012-02-07 00:59:59.000 3599 
2012-02-07 01:00:00.000 2012-02-07 01:59:59.000 3599 
2012-02-07 02:00:00.000 2012-02-07 02:59:59.000 3599 
2012-02-07 03:00:00.000 2012-02-07 03:59:59.000 3599 
2012-02-07 04:00:00.000 2012-02-07 04:59:59.000 3599 
2012-02-07 05:00:00.000 2012-02-07 05:59:59.000 3599

.. ..

2012-12-08 18:00:00.000 2012-12-08 18:59:59.000 3599 
2012-12-08 19:00:00.000 2012-12-08 19:59:59.000 3599 
2012-12-08 20:00:00.000 2012-12-08 20:59:59.000 3599 
2012-12-08 21:00:00.000 2012-12-08 21:59:59.000 3599 
2012-12-08 22:00:00.000 2012-12-08 22:59:59.000 3599 
2012-12-08 23:00:00.000 2012-12-08 23:59:17.000 3557

希望有人会发现它有用。

答

有了期待您的预计表，你要在两个时间之间获得型差分在second 。

SELECT DATEDIFF(SECOND, '2012-02-29 09:00:00.000', '2012-02-29 09:59:00.000')只给出3540是第二个的差异。

为了得到小时的时差，你可以试试这个代码：

SELECT DATEDIFF(hour, '2012-02-06 23:59:00.000', '2012-02-06 23:59:00.000')

我希望结果分解为小时间隔和间隔时间之间的小时数 – 2012-07-13 10:28:14

请阅读更新的答案...您需要获得第一个小时的差异，然后得到第二个差异，这是我在答案中更新的。 – 2012-07-13 10:29:56

对不起，应该是秒 – 2012-07-13 10:30:01

答

DATEDIFF(hour, [start], [end])

见description on w3schools。

答

DECLARE @start_date datetime = CONVERT(DATETIME,'2012-02-06 23:59:01.000', 20); 
DECLARE @end_date datetime = CONVERT(DATETIME,'2012-12-08 23:59:17.000', 20); 

-- Using a recursive query after round down to full hours avoids a loop. The resulting intervals should be easier to use that way, e.g. you can but don't have to insert them into a table variable. 
SET @start_date = DATEADD(HOUR, DATEPART(HOUR, @start_date), CAST(FLOOR(CAST(@start_date AS float)) AS datetime)); 
SET @end_date = DATEADD(HOUR, DATEPART(HOUR, @end_date), CAST(FLOOR(CAST(@end_date AS float)) AS datetime)); 
WITH RecursiveTimeIntervals AS 
(SELECT @start_date Interval 
UNION ALL SELECT DATEADD(HOUR, 1, r.Interval) 
FROM RecursiveTimeIntervals r 
WHERE r.Interval < @end_date) 
SELECT * 
FROM RecursiveTimeIntervals 
ORDER BY 1 
OPTION (MAXRECURSION 0)

获取日期范围之间的时间间隔

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