嵌套的PHP数组JSON
所以我的代码在这里:嵌套的PHP数组JSON
$featurecollection = ("FeatureCollection");
$test[] = array (
"type" => $featurecollection,
$features[] = array($images)
);
file_put_contents($cache,json_encode($test));
结果如下JSON:
[
{
"type":"feature",
"0":[
[
{
"title":"some title",
"src":"value",
"lat":"value",
"lon":"value"
},
{
"title":"some title",
...
但我需要的东西鸟巢不同,我是如何在PHP阵列上困惑应该被构造为获得如下结果:
{
"type":"FeatureCollection",
"features":[
{
"type":"Feature",
"geometry":{
"coordinates":[
-94.34885,
39.35757
],
"type":"Point"
},
"properties":{
"latitude":39.35757,
"title":"Kearney",
"id":919,
"description":"I REALLY need new #converse, lol. I've had these for three years. So #destroyed ! :(Oh well. Can't wait to get a new pair and put my #rainbow laces through. #gay #gaypride #bi #proud #pride #colors #shoes #allstar #supporting ",
"longitude":-94.34885,
"user":"trena1echo5",
"image":"http://images.instagram.com/media/2011/09/09/ddeb9bb508c94f2b8ff848a2d2cd3ece_7.jpg",
"instagram_id":211443415
}
},
这个php数组看起来像什么?我被一切都嵌套但仍然有一个关键价值的方式抛弃。
以下是我会代表,在PHP:
array(
'type' => 'FeatureCollection',
'features' => array(
array(
'type' => 'Feature',
'geometry' => array(
'coordinates' => array(-94.34885, 39.35757),
'type' => 'Point'
), // geometry
'properties' => array(
// latitude, longitude, id etc.
) // properties
), // end of first feature
array(...), // etc.
) // features
)
因此,要获得该结构中,每个特征必须是一个关联数组:
- 类型,
- 几何 - 一个关联数组:
- 坐标 - 一个索引值的数组,
- 类型
- 性质 - 如纬度,经度,ID值等的关联数组
它的时间等,这些当我宁愿列表(array(1, 2, 3)
)和字典或地图之间区分语言(array('a' => 1, 'b' => 2)
)。
谢谢!现在开始工作...... – 2012-04-15 19:38:40
好吧,我如何循环这些变量(创建多个功能)?我得到如何构建这个数组,然后将其编码为json,我只是难以解决如何使用多个实例来构建它。 – 2012-04-17 10:24:39
你从哪里获得数据(以及以何种结构)?我会用这个信息创建一个新的问题来获得更快的响应:) – Ross 2012-04-17 12:35:02
在PHP 5.4以上:
$array = [
'type' => 'FeatureCollection',
'features' => [
[
'type' => 'Feature',
'geometry' => [
'coordinates' => [-94.34885, 39.35757],
'type' => 'Point'
], // geometry
'properties' => [
// latitude, longitude, id etc.
] // properties
], // end of first feature
[] // etc.
] // features
];
下面是使用标题下方 头( '内容类型=>应用/ JSON')的JSON输出; echo json_encode($ array);
{
"type": "FeatureCollection",
"features": [
{
"type": "Feature",
"geometry": {
"coordinates": [
-94.34885,
39.35757
],
"type": "Point"
},
"properties": []
},
[]
]
}
我*想*您只需要更换'$功能[] =数组($图片)'和' '特点'=>阵列($图片)',不过我'm pretty n00b w/PHP ... – 2012-04-15 19:25:45