DATEDIFF（月）

Question

我有则DateDiff（月的两个日期之间的数）的问题

当我试试这个：

SELECT 
(CASE 
WHEN X IS NOT NULL THEN 

CONVERT(varchar(4), DATEDIFF(YEAR, Y, C)) + ' years ' 

ELSE 
CONVERT(varchar(4), DATEDIFF(YEAR, A, GETDATE())) + ' years '+ 
CAST(DATEDIFF(mm, DATEADD(yy, DATEDIFF(yy,GETDATE(),b), S), GETDATE()) AS varchar(4)) +' month '+ 
CAST(DATEDIFF(dd, DATEADD(mm, DATEDIFF(mm, DATEADD(yy, DATEDIFF(yy, c, GETDATE()), e), GETDATE()), DATEADD(yy, DATEDIFF(yy, f, GETDATE()), g)), GETDATE()) AS varchar(2)) +' day' end) as result 

FROM g INNER JOIN k ON M=U 
WHERE T=XX order by Y; 

结果是这样的：2年342个月2天

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但它应该是这样的：2年3个月2日前例如，

有人可以请指出我在正确的方向。谢谢。

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正确答案：

CONVERT(varchar(4), DATEDIFF(dd, x, GETDATE())/365) + ' år '+ 

CONVERT(varchar(4), DATEDIFF(MONTH, x, GETDATE()) % 12) + ' måneder '+ 

CAST(DATEDIFF(dd, DATEADD(mm, DATEDIFF(mm, DATEADD(yy, DATEDIFF(yy, x, GETDATE()), x), GETDATE()), 
DATEADD(yy, DATEDIFF(yy, x, GETDATE()), x)), GETDATE()) AS varchar(2)) +' dag ' end) as Y, 

Answer 1

你需要做一些额外的计算。看看从这里采取了这种

declare @AsOnDate datetime 
declare @mdob datetime 
set @AsOnDate = GETDATE() 
set @mdob = '2014-12-22' 
Select 
"Years" = CASE 
WHEN (DATEPART(DAY , @mdob)) > (DATEPART(DAY , @AsOnDate)) 
and (DATEPART(Month,@mdob)) = (DATEPART(Month, @AsOnDate)) 
THEN ((datediff(month,@mdob,@AsOnDate)-1)/12) 
ELSE (datediff(month,@mdob,@AsOnDate)/12) 
END, 
"Months" = CASE 
WHEN (DATEPART(DAY , @mdob)) > (DATEPART(DAY , @AsOnDate)) 
and (DATEPART(Month,@mdob)) = (DATEPART(Month,@AsOnDate)) 
THEN ((datediff(month,@mdob,@AsOnDate)-1)% 12) 
ELSE (datediff(month,@mdob,@AsOnDate)% 12) 
END 

解决方案： https://www.sqlservercentral.com/Forums/Dialogs/PostDetails.aspx?PostID=1423756