如何在VBA(Excel)中以毫秒为单位获取DateDiff值?
答
你可以使用方法描述here如下: -
创建一个名为StopWatch
将下面的代码StopWatch
类模块中一个新的类模块:
Private mlngStart As Long
Private Declare Function GetTickCount Lib "kernel32"() As Long
Public Sub StartTimer()
mlngStart = GetTickCount
End Sub
Public Function EndTimer() As Long
EndTimer = (GetTickCount - mlngStart)
End Function
您使用的代码如下:
Dim sw as StopWatch
Set sw = New StopWatch
sw.StartTimer
' Do whatever you want to time here
Debug.Print "That took: " & sw.EndTimer & "milliseconds"
其他方法描述使用VBA定时器功能,但这只能精确到百分之一秒(厘秒)。
答
除了通过AdamRalph(GetTickCount()
)中描述的方法,你可以这样做:
- 使用
QueryPerformanceCounter()
和QueryPerformanceFrequency()
API函数
How do you test running time of VBA code? - 或者,对于环境,而无需访问的Win32 API(如VBScript):
http://ccrp.mvps.org/(查看“高性能定时器”的可安装COM对象的下载部分,它们是免费的。)
答
如果你只需要在Centiseconds中花费的时间,那么你就不需要TickCount API。您可以使用所有Office产品中存在的VBA.Timer方法。如果你想要去的微秒
Public Sub TestHarness()
Dim fTimeStart As Single
Dim fTimeEnd As Single
fTimeStart = Timer
SomeProcedure
fTimeEnd = Timer
Debug.Print Format$((fTimeEnd - fTimeStart) * 100!, "0.00 "" Centiseconds Elapsed""")
End Sub
Public Sub SomeProcedure()
Dim i As Long, r As Double
For i = 0& To 10000000
r = Rnd
Next
End Sub
答
的GetTickCount和性能计数器需要.. 对于millisenconds你可以用一些这样的事..
'at the bigining of the module
Private Type SYSTEMTIME
wYear As Integer
wMonth As Integer
wDayOfWeek As Integer
wDay As Integer
wHour As Integer
wMinute As Integer
wSecond As Integer
wMilliseconds As Integer
End Type
Private Declare Sub GetLocalTime Lib "kernel32" (lpSystemTime As SYSTEMTIME)
'In the Function where you need find diff
Dim sSysTime As SYSTEMTIME
Dim iStartSec As Long, iCurrentSec As Long
GetLocalTime sSysTime
iStartSec = CLng(sSysTime.wSecond) * 1000 + sSysTime.wMilliseconds
'do your stuff spending few milliseconds
GetLocalTime sSysTime ' get the new time
iCurrentSec=CLng(sSysTime.wSecond) * 1000 + sSysTime.wMilliseconds
'Different between iStartSec and iCurrentSec will give you diff in MilliSecs
答
您还可以使用=NOW()
公式calcilated在细胞:
Dim ws As Worksheet
Set ws = Sheet1
ws.Range("a1").formula = "=now()"
ws.Range("a1").numberFormat = "dd/mm/yyyy h:mm:ss.000"
Application.Wait Now() + TimeSerial(0, 0, 1)
ws.Range("a2").formula = "=now()"
ws.Range("a2").numberFormat = "dd/mm/yyyy h:mm:ss.000"
ws.Range("a3").formula = "=a2-a1"
ws.Range("a3").numberFormat = "h:mm:ss.000"
var diff as double
diff = ws.Range("a3")
答
道歉唤醒这个老帖子,但我得到了一个答案:
写这样的毫秒功能:
Public Function TimeInMS() As String
TimeInMS = Strings.Format(Now, "HH:nn:ss") & "." & Strings.Right(Strings.Format(Timer, "#0.00"), 2)
End Function
使用此功能在您的子:
Sub DisplayMS()
On Error Resume Next
Cancel = True
Cells(Rows.Count, 2).End(xlUp).Offset(1) = TimeInMS()
End Sub
注意的是,虽然`GetTickCount`在millseconds解决,其具有约16毫秒一个精度[请参阅此MSDN文章](https://msdn.microsoft.com/en-us/library/windows/desktop/ms724408%28v=vs.85%29.aspx) – 2015-01-26 02:57:11
只是一个问题:如何计算2个值之间的时间差存储在Excel中? – patex1987 2017-01-18 10:00:08