为每个缺失值的组添加一行
问题描述:
每个篮子可容纳的水果总数为10.对于每个篮子,如果数量为10且缺少一个水果,我想为该篮子添加一行说那个水果的数量是0。 以下是生成数据帧的代码。为每个缺失值的组添加一行
Basket <- c("A","A","B","B","C","C","C")
Fruit <- c("Apple","Orange","Apple","Orange","Orange","Apple", "Guava")
count <- c("5","5","7","3","2","6","4")
data <- data.frame(Basket,Fruit,count)
Basket Fruit count
1 A Apple 5
2 A Orange 5
3 B Apple 7
4 B Guava 3
5 C Orange 2
6 C Apple 6
7 C Guava 4
我想基本上像它看起来是这样的:
Basket Fruit count
1 A Apple 5
2 A Orange 5
4 A Guava 0
5 B Apple 7
6 B Orange 0
7 B Guava 3
8 C Orange 2
9 C Apple 6
10 C Guava 4
不完全相信,如果循环将是一种有效的方法,但开放的建议。目标是为每个水果在群体中获得准确的平均值。
答
将您data.frame宽格式,以0而不是来港填充它,然后将其转换回高大格式:
count <- c(5,5,7,3,2,6,4) # should be integers, not strings
data <- data.frame(Basket,Fruit,count)
d1 <- tidyr::spread(data, Fruit, count, fill = 0)
d2 <- tidyr::gather(d1, Fruit, count, -Basket)
答
data <- data.frame(Basket,Fruit,count,stringsAsFactors = F)
full = merge(
data,
expand.grid(
Basket=data$Basket,
Fruit=data$Fruit
),
all.y=T
)
full$count = ifelse(is.na(full$count), 0, full$count)
答
我知道有扩散和聚集funcion,从tydir包
library(tidyr)
data <- data %>%
spread(Fruit, count, fill = 0) %>%
gather(Fruit, count, -Basket)
把0,计数值必须是整数,而不是因素。 为此,您可以用
data$count <- as.integer(data$count))
答
次数仅工作,如果只有1个缺失水平的水果,否则应该按预期工作
Basket <- c("A","A","B","B","C","C","C")
Fruit <- c("Apple","Orange","Apple","Orange","Orange","Apple", "Guava")
count <- c(5,5,7,3,2,6,4)
data <- data.frame(Basket,Fruit,count, stringsAsFactors = FALSE)
fruit_levels <- levels(as.factor(data$Fruit))
append_df <- data.frame(Basket = NA, Fruit = NA, count = NA)
for(i in levels(as.factor(data$Basket))){
temp_df <- filter(data, Basket == i)
temp_count <- 10 - sum(temp_df$count)
if(length(levels(as.factor(temp_df$Fruit))) != length(fruit_levels)){
temp_fruit <- cbind.data.frame(fruit = fruit_levels, count = ifelse(fruit_levels %in% temp_df$Fruit, 0, 1))
temp_fruit2 <- filter(temp_fruit, count == 1) %>% select(fruit)
temp_fruit3 <- temp_fruit2[,1] %>% as.character()
temp_df_to_append <- data.frame(Basket = i, Fruit = temp_fruit3, count = temp_count)
append_df <- rbind.data.frame(append_df, temp_df_to_append)
}
}
data <- rbind.data.frame(data, append_df[-1,]) %>% arrange(Basket)
Nvm。这工作! – rockboy23
关于不匹配属性的抱怨可能是由于字符变量被视为“因素”。尝试在'data.frame'结构中添加'stringsAsFactors = FALSE'。或者更好的是,使用'tibble :: data_frame'来代替。 –