如何使用smack获得IQ标签?
问题描述:
实际上,问题是当我的xmpp客户端发送好友邀请,然后收件人已批准邀请时,openfire服务器再次向发起者/邀请发送者推送要授权的订阅数据包,这就是为什么我要防止这种情况通过使用IQ标签自动进行过滤,然后自动对其进行授权。如何使用smack获得IQ标签?
但PacketListener,我不能让智商的标签......
我怎样才能做到这一点?
@Override
public void processPacket(Packet packet) {
Log.i(TAG, "SECOND subscription");
Log.d(TAG, "SECOND: "+packet.toXML());
if (packet instanceof Presence) {
Presence p = (Presence) packet;
Log.d(TAG, "TYPE-Presence: "+p.getType());
if (p.getType() != Presence.Type.subscribe)
return;
String from = p.getFrom();
Log.d(TAG, "PACKET from: "+from);
Notification notification = new Notification(android.R.drawable.stat_notify_more, mService.getString(
R.string.AcceptContactRequest, from), System.currentTimeMillis());
notification.flags = Notification.FLAG_AUTO_CANCEL;
Intent intent = new Intent(mService, Subscription.class);
intent.setData(Contact.makeXmppUri(from));
notification.setLatestEventInfo(mService, from, mService
.getString(R.string.AcceptContactRequestFrom, from), PendingIntent.getActivity(mService, 0,
intent, PendingIntent.FLAG_ONE_SHOT));
int id = p.hashCode();
mService.sendNotification(id, notification);
}
}
答
可以通过使用“IQTypeFilter”过滤器过滤输入的IQ。这是说明该方法的示例代码。
connection.connect();
/* packet listener: listen for incoming messages of type IQ on the connection (whatever the buddy) */
PacketFilter filter = new IQTypeFilter(IQ.Type.SET); // or IQ.Type.GET etc. according to what you like to filter.
connection.addPacketListener(new PacketListener() {
public void processPacket(Packet packet) {
// HERE YOU PUT YOUR CODE TO HANDLE THE IQ MESSAGE
}
}, filter);
工作太好了!谢谢! – user724861 2012-04-08 15:12:21
您能否详细说明您的答案。其实我不知道如何处理IQ消息 – 2014-03-10 11:00:12