用JQuery/PHP解析嵌套的JSON字符串对象?
问题描述:
这是我工作的页面.... http://fremontchurch.net/json_test/用JQuery/PHP解析嵌套的JSON字符串对象?
这是 http://fremontchurch.net/json_test/posts.php
我想有列出曲目名称的列表,并通过简单的HTML链接链接的JSON <a href="URL_GOES_HERE">TRACK NAME GOES HERE</a>
到它的网址
我得到了一切,只是它的嵌套部分不断出现“[对象对象],[对象对象],[对象对象]”等......每个巢都有两个项目的曲目名称和网址...什么是正确的方法来做到这一点?
继承人一个对象从我的JSON ...
{
"id":"All Things Are Possible",
"key":"All Things Are Possible",
"doc":"All Things Are Possible",
"album":"All Things Are Possible",
"artwork":"http://godsgypsychristianchurch.net/music_artwork/DEFAULT_COVER2.png",
"baseurl":"http://www.godsgypsychristianchurch.net/music",
"church":"Atlanta GA",
"des":"All Things Are Possible from the Atlanta GA Church, Pastor Nick White",
"tracks":[
{"name":"1 Intro",
"url":"/Atlanta%20GA/All%20things%20are%20possible/01%20Intro.mp3"},
{"name":"2 Wo si O Drom",
"url":"/Atlanta%20GA/All%20things%20are%20possible/02%20Wo%20si%20O%20drom.mp3"},
{"name":"3 Nas Murrgo Shov",
"url":"/Atlanta%20GA/All%20things%20are%20possible/03%20Nas%20murrgo%20shov.mp3"},
{"name":"4 To Cho Vos",
"url":"/Atlanta%20GA/All%20things%20are%20possible/04%20To%20cho%20vos.mp3"},
{"name":"5 Tu Son Kai Sastridas",
"url":"/Atlanta%20GA/All%20things%20are%20possible/05%20Tu%20son%20kai%20sastridas.mp3"},
{"name":"6 Now I Am Strong",
"url":"/Atlanta%20GA/All%20things%20are%20possible/06%20Now%20I%20am%20strong.mp3"},
{"name":"7 Sorr Nevee",
"url":"/Atlanta%20GA/All%20things%20are%20possible/07%20Zorr%20nevee.mp3"},
{"name":"8 Preaching",
"url":"/Atlanta%20GA/All%20things%20are%20possible/08%20Preaching.mp3"},
{"name":"9 Arkadyan Amey",
"url":"/Atlanta%20GA/All%20things%20are%20possible/09%20Arkadyan%20amey.mp3"},
{"name":"10 O Christo Ka Wudarr",
"url":"/Atlanta%20GA/All%20things%20are%20possible/10%20O%20Christo%20ka%20wudarr.mp3"},
{"name":"11 Eloi, Eloi",
"url":"/Atlanta%20GA/All%20things%20are%20possible/11%20Eloi%2C%20Eloi.mp3"},
{"name":"12 Amadow Dell",
"url":"/Atlanta%20GA/All%20things%20are%20possible/12%20Amadow%20Dell.mp3"},
{"name":"13 Sastiar Amey Devla",
"url":"/Atlanta%20GA/All%20things%20are%20possible/13%20Sastiar%20amey%20Devla.mp3"},
{"name":"14 Tu Skepeese",
"url":"/Atlanta%20GA/All%20things%20are%20possible/14%20Tu%20skepeese.mp3"},
{"name":"15 Dov Ma Godgee",
"url":"/Atlanta%20GA/All%20things%20are%20possible/15%20Dov%20ma%20godgee.mp3"},
{"name":"16 The Lord is my strength",
"url":"/Atlanta%20GA/All%20things%20are%20possible/16%20The%20Lors%20is%20my%20strength.mp3"}
]
}
所有继承人我的代码的HTML/jQuery的/ PHP
<html>
<body>
<div id="content">
</div>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var url="posts.php";
$.getJSON(url,function(json){
$.each(json.posts,function(i,post){
$("#content").append(
'<div class="post">'+
'<h1>'+post.album+'</h1>'+
'<p><img src="'+post.artwork+'"width="250"></img></p>'+
'<p><strong>'+post.church+'</strong></p>'+
'<p>Description: <strong>'+post.des+'</strong></p>'+
'<p>Base url: <em>'+post.baseurl+'</em></p>'+
'<p>Tracks: <li>'+post.tracks+'</li></p>'+
'<hr>'+
'</div>'
);
});
});
});
</script>
</body>
</html>
,因为我还挺新来请回复将全额代码这种编码,有时我知道把它放在哪里...任何帮助将非常感谢,谢谢...
答
以同样的方式,您使用each
遍历帖子,您可以使用each
来遍历曲目。我已经在下面包含完整的代码。
<html>
<body>
<div id="content">
</div>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var url="posts.php";
$.getJSON(url,function(json){
$.each(json.posts,function(i,post){
// Here we generate a fragment for the tracks.
var tracks = '';
$.each(post.tracks, function(j, track) {
tracks += '<a href="' + track.url + '">' + track.name + '</a>';
})
$("#content").append(
'<div class="post">'+
'<h1>'+post.album+'</h1>'+
'<p><img src="'+post.artwork+'"width="250"></img></p>'+
'<p><strong>'+post.church+'</strong></p>'+
'<p>Description: <strong>'+post.des+'</strong></p>'+
'<p>Base url: <em>'+post.baseurl+'</em></p>'+
'tracks' +
'<hr>'+
'</div>'
);
});
});
});
</script>
答
你需要循环在post.tracks每个项目,包括之前收集的信息转换成字符串,这样的事情:这里
$.each(json.posts,function(i,post){
var content,
trackInfo = '',
tracks = post.tracks;
// loop over the tracks and collect info
$.each(tracks, function (i) {
trackInfo += '<a href="' + tracks[i].url + '">' + tracks[i].name + '</a> ';
});
content = '<div class="post">'+
'<h1>'+post.album+'</h1>'+
'<p><img src="'+post.artwork+'"width="250"></img></p>'+
'<p><strong>'+post.church+'</strong></p>'+
'<p>Description: <strong>'+post.des+'</strong></p>'+
'<p>Base url: <em>'+post.baseurl+'</em></p>'+
'<p>Tracks: <li>'+ trackInfo +'</li></p>';
'<hr>'+
'</div>'
$("#content").append(content);
});
你不不需要解析JSON就可以使用它,它已经是一个对象! – markus