多次打印相同的东西

多次打印相同的东西

问题描述:

我不知道是什么问题,但它多次保持打印同一个东西。如果有人能帮助我,将不胜感激。谢谢多次打印相同的东西

from bs4 import BeautifulSoup 
from urllib.parse import urlparse 
import urllib.request 


req = urllib.request.Request('http://shopnicekicks.com/products/a-ma-maniere-x-diadora-n9000-mens-brown-sugar.xml') 
res = urllib.request.urlopen(req) 
end = res.geturl() 
soup = BeautifulSoup(res, 'lxml') 
parsed = urlparse(end) 


for variant in soup.variants.find_all("id", {"type": "integer"}): 
    cart = 'http://'+parsed.netloc+'/cart/' +variant.text+':1' 
    for size in soup.variants.find_all('title'): 
     print(cart, size.text) 
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应该打印什么?那么这是如何从输入中推导出来的呢?它实际上打印了什么? – interjay

+0

它假设打印像这样: http://shopnicekicks.com/cart/23839239105:1 8 http://shopnicekicks.com/cart/23839239169:1 8.5 http://shopnicekicks.com/cart/23839239233 :1 9 http://shopnicekicks.com/cart/23839239297:1 9.5 http://shopnicekicks.com/cart/23839239361:1 10 http://shopnicekicks.com/cart/23839239425:1 10.5 http ://shopnicekicks.com/cart/23839239489:1 11 http://shopnicekicks.com/cart/23839239553:1 12 http://shopnicekicks.com/cart/23839239617:1 13 – EdBiz

你的发现太高了,所以你最终得到文档中每个标识的所有标题。在每个变体内部找到发现。

from bs4 import BeautifulSoup 
from urllib.parse import urlparse 
import urllib.request 


req = urllib.request.Request('http://shopnicekicks.com/products/a-ma-maniere-x-diadora-n9000-mens-brown-sugar.xml') 
res = urllib.request.urlopen(req) 
end = res.geturl() 
soup = BeautifulSoup(res, 'lxml') 
parsed = urlparse(end) 

for variant in soup.variants.find_all("variant"): 
    cart = 'http://'+parsed.netloc+'/cart/' +variant.id.text+':1' 
    size = variant.find("title") 
    print(cart, size.text) 
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的链接非常感谢。 – EdBiz

如果您的print(cart, size.text)print(size, size.text)

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不,因为我想打印购物车 – EdBiz