如何获取div标签中的所有li标签

Question

我在网站上获取公司和产品详细信息。 它有div标签，里面有li标签，我想要获得div标签中的所有li标签。 我使用python 3.5.1和BeautifulSoup

我的代码：

from bs4 import BeautifulSoup 
import urllib.request 
import re 
r = urllib.request.urlopen('http://i.cantonfair.org.cn/en/ExpExhibitorList.aspx?k=glassware') 
soup = BeautifulSoup(r, "html.parser") 

links = soup.find_all("a", href=re.compile(r"expexhibitorlist\.aspx\?categoryno=[0-9]+")) 
linksfromcategories = ([link["href"] for link in links]) 

string = "http://i.cantonfair.org.cn/en/" 
linksfromcategories = [string + x for x in linksfromcategories] 

for link in linksfromcategories: 
    response = urllib.request.urlopen(link) 
    soup2 = BeautifulSoup(response, "html.parser") 
    links2 = soup2.find_all("a", href=re.compile(r"\ExpExhibitorList\.aspx\?categoryno=[0-9]+")) 
    linksfromsubcategories = ([link["href"] for link in links2]) 
    linksfromsubcategories = [string + x for x in linksfromsubcategories] 
    for link in linksfromsubcategories: 
     response = urllib.request.urlopen(link) 
     soup3 = BeautifulSoup(response, "html.parser") 
     links3 = soup3.find_all("a", href=re.compile(r"\ExpExhibitorList\.aspx\?categoryno=[0-9]+")) 
     linksfromsubcategories2 = ([link["href"] for link in links3]) 
     linksfromsubcategories2 = [string + x for x in linksfromsubcategories2] 
     for link in linksfromsubcategories2: 
      response2 = urllib.request.urlopen(link) 
      soup4 = BeautifulSoup(response2, "html.parser") 
      companylink = soup4.find_all("a", href=re.compile(r"\expCompany\.aspx\?corpid=[0-9]+")) 
      companylink = ([link["href"] for link in companylink]) 
      companylink = [string + x for x in companylink] 
      for link in companylink: 
       response3 = urllib.request.urlopen(link) 
       soup5 = BeautifulSoup(response3, "html.parser") 
       companydetail = soup5.find_all("div", id="contact") 
       for element in companydetail: 
        companyname = element.a[0].get_text() 
        print (companyname) 
        companyaddress = element.a[1].get_text() 
        print (companyaddress)And I am getting error 

而且我得到错误

Traceback (most recent call last): 
    File "D:\python\phase3.py", line 54, in <module> 
    lis = companydetail.find_all('li') 
AttributeError: 'ResultSet' object has no attribute 'find_all' 

Answer 1

companydetail是ResultSet。也就是说，它是一个包含许多元素的可迭代对象（如list或set）。由于您尝试在此ResultSet对象上尝试调用.find_all()，因此发生此错误。你应该通过这个对象像下面这样迭代，并呼吁元素find_all()在ResultSet：

lis = [ li for d.find_all('li') for d in companydetail ]