警告：mysqli_fetch_array（）预计在PHP

Question

最多2个参数我试图创建一个数据库迭代分页。这是我的代码到目前为止。

$per_page = 5; 
$result = mysqli_query($connection,"SELECT * FROM inquiries"); 
$total_records = mysqli_num_rows($result); 
$total_pages = ceil($total_records/$per_page); 

if (isset($_GET['page'])) { 
    $show_page = $_GET['page']; 
    if ($show_page > 0 && $show_page <= $total_pages) { 
     $start = ($show_page - 1) * $per_page; 
     $end = $start + $per_page; 
    } else { 
     $start = 0; 
     $end = $per_page; 
    } 
} else { 
    $start = 0; 
    $end = $per_page; 
} 
$page = intval($_GET['page']); 

$tpages=$total_pages; 
if ($page <= 0) 
    $page = 1; 
for ($i = $start; $i < $end; $i++) { 
    if ($i == $total_records) { 
     break; 
    } 
    echo mysqli_fetch_array($result,$i,'message'); 

那。由于它造成以下错误。

警告：mysqli_fetch_array（）预计至多2个参数，在3给出..

有人可以帮我解决这个错误。

Answer 1

您可以为总数第一次查询然后SELECT FOUND_ROWS();尝试SQL_CALC_FOUND_ROWS与限制。

SELECT SQL_CALC_FOUND_ROWS, Id, Name FROM my_table WHERE <give your condition> LIMIT 0, 10; 

# Find total rows 
SELECT FOUND_ROWS();