将平面结构转换为分层结构
我需要创建能够将平面对象转换为递归对象的功能。这是我的例子: 我有平面数组:将平面结构转换为分层结构
var flatArray = [
{
Description: "G",
guid: "c8e63b35",
parent: null,
},
{
Description: "Z",
guid: "b1113b35",
parent: "c8e63b35",
},
{
Description: "F",
guid: "d2cc2233",
parent: "b1113b35",
},
{
Description: "L",
guid: "a24a3b1a",
parent: null,
},
{
Description: "K",
guid: "cd3b11caa",
parent: "a24a3b1a",
},
]
的结果应该是:
recursiveArray = [
{
Description: "G",
guid: "c8e63b35",
parent: null,
Children: [
{
Description: "Z",
guid: "b1113b35",
parent: "c8e63b35",
Children: [
{
Description: "F",
guid: "d2cc2233",
parent: "b1113b35",
}
]
},
]
},
{
Description: "L",
guid: "a24a3b1a",
parent: null,
Children: [
{
Description: "K",
guid: "cd3b11caa",
parent: "a24a3b1a",
}
}
]
请帮我看看这样做的方式。一个有效的算法将不胜感激,因为我有理解如何正确地做到这一点的问题。在每种情况下,我需要为递归结构中的checked元素查找特定位置,并将其推送到finded元素children数组中。我认为这很愚蠢和低效。有什么办法可以做到这一点快速和高效?
编辑:递归数组格式错误。现在应该没问题。 我的数组没有以任何方式排序。
这一个工作很好,易于阅读:
function flatToHierarchy (flat) {
var roots = [] // things without parent
// make them accessible by guid on this map
var all = {}
flat.forEach(function(item) {
all[item.guid] = item
})
// connect childrens to its parent, and split roots apart
Object.keys(all).forEach(function (guid) {
var item = all[guid]
if (item.parent === null) {
roots.push(item)
} else if (item.parent in all) {
var p = all[item.parent]
if (!('Children' in p)) {
p.Children = []
}
p.Children.push(item)
}
})
// done!
return roots
}
是的,这很简单,功能。谢谢! –
此代码可以找到儿童的孩子吗?我认为这需要递归功能。 – Gaslan
@Gurkanat是的,它适用于4级结构。我在接受这个答案之前检查了这一点。 –
我试图用伪代码写出算法,最后得到了几乎可行的JS代码(可能需要一些额外的验证/检查),但是显示了问题的一般方法。
//Lets separate children (nodes with a parent) from roots (nodes without a parent)
var children = flatArray.filter(function(object){
return object.parent !== null;
});
var roots = flatArray.filter(function(object){
return object.parent === null;
});
//And add each child to the nodes tree
children.foreach(function(child){
recursiveAdd(roots, child);
});
//To add a children node, node tree is searched recursively for a parent
function recursiveAdd(nodes, child){
nodes.foreach(function(parent){
if(parent.guid === child.parent){
parent.Children = parent.Children | [];
parent.Children.add(child);
} else if(parent.Children) {
recursiveAdd(parent.Children, child);
}
});
}
//Temporary children array can be garbage collected
children = null;
//Resulting node tree
var recursiveArray = roots;
这个递归函数可能对你不错:
var flatArray = [{
Description: "G",
guid: "c8e63b35",
parent: null,
Children: []
}, {
Description: "Z",
guid: "b1113b35",
parent: "c8e63b35",
Children: []
}, {
Description: "F",
guid: "d2cc2233",
parent: "b1113b35",
Children: []
}, {
Description: "L",
guid: "a24a3b1a",
parent: null,
Children: []
}, {
Description: "K",
guid: "cd3b11caa",
parent: "a24a3b1a",
Children: []
}, ];
for (var i = 0; i < flatArray.length; i++) {
recursive(flatArray[i]);
}
function recursive(a) {
for (var i = 0; i < flatArray.length; i++) {
if (flatArray[i].parent == a.guid) {
var b = flatArray[i];
recursive(b);
a.Children.push(b);
}
}
}
console.log(flatArray)
这是我会怎么做:
var flatArray = [{
Description: "G",
guid: "c8e63b35",
parent: null,
}, {
Description: "Z",
guid: "b1113b35",
parent: "c8e63b35",
}, {
Description: "F",
guid: "d2cc2233",
parent: "b1113b35",
}, {
Description: "L",
guid: "a24a3b1a",
parent: null,
}, {
Description: "K",
guid: "cd3b11caa",
parent: "a24a3b1a",
}];
var recursiveArray = unflatten(flatArray);
alert(JSON.stringify(recursiveArray, null, 4));
<script>
function unflatten(items) {
return items.reduce(insert, {
res: [],
map: {}
}).res;
}
function insert(obj, item) {
var parent = item.parent;
var map = obj.map;
map[item.guid] = item;
if (parent === null) obj.res.push(item);
else {
var parentItem = map[parent];
if (parentItem.hasOwnProperty("Children"))
parentItem.Children.push(item);
else parentItem.Children = [item];
}
return obj;
}
</script>
当然,这只适用于您的flatArray
具有每个父母都出现在其子女面前的属性。
希望有所帮助。
这是非常好的解决方案,也许我根据你的答案学习新的东西。谢谢! :) –
var flatArray = [
{
Description: "G",
guid: "c8e63b35",
parent: null,
},
{
Description: "Z",
guid: "b1113b35",
parent: "c8e63b35",
},
{
Description: "F",
guid: "d2cc2233",
parent: "b1113b35",
},
{
Description: "L",
guid: "a24a3b1a",
parent: null,
},
{
Description: "K",
guid: "cd3b11caa",
parent: "a24a3b1a",
},
];
//for printing
function htmlPrint(obj) {
document.write('<pre>'+JSON.stringify(obj,null,2)+'</pre>');
};
var guids = {};
var roots = [];
flatArray.forEach(function(node){
guids[node.guid] = node; //save into a hash
node.Children = []; //make sure it has a children array
//save it as root if it is a root
if(node.parent === null){ roots.push(node);}
});
flatArray.forEach(function(node){
//if it has a parent, add self to parent's children
var parent = guids[node.parent];
if(parent) parent.Children.push(node);
});
htmlPrint(roots);
,你可以这样做: 'VAR recoursiveArray = []; recoursiveArray.push(flatArray [0]);recoursiveArray [0] .children = []; recoursiveArray [0] .children.push(flatArray [1]);' –
不应该''L''对象有''c8e63b35''作为它的父类,而不是'null'? – Oka
是你的数组以某种方式排序? – franciscod