通过变量获取json对象值
问题描述:
{
"data": [{
"data": [{
"Part": "1.75 L ICON (Glass)",
"ProductionCounts": 1012620
}, {
"Part": "1.75 L Marg Mix (PET)",
"ProductionCounts": 1003278
}, {
"Part": "1.75 L Authentics (PET)",
"ProductionCounts": 457615
}, {
"Part": "1.0 L Margarita Mix/PET",
"ProductionCounts": 660982
}, {
"Part": "other",
"ProductionCounts": 1571985
}]
}, ],
"dateArray": ["2011-01-01", "2011-02-01", "2011-03-01", "2011-04-01", "2011-05-01", "2011-06-01", "2011-07-01", "2011-08-01", "2011-09-01", "2011-10-01", "2011-11-01"],
"xAxis": "Part",
"yAxis": "ProductionCounts",
"interestingMoments": []
}
我想访问json对象的值。每次获取json对象时,json对象的字段名都会有所不同,所以我将xAxis和yAxis中的字段名称分开发送。通过变量获取json对象值
当我试图访问jsonData.data [0] .data [0] .xAxis时,它给我未定义的值而不是值。 我不能这样访问,因为字段名称每次都会有所不同,所以我试图通过变量jsonData.data [0] .data [0] .Part来访问它。
答
试试这个:
var data={
"data": [{
"data": [{
"Part": "1.75 L ICON (Glass)",
"ProductionCounts": 1012620
}, {
"Part": "1.75 L Marg Mix (PET)",
"ProductionCounts": 1003278
}, {
"Part": "1.75 L Authentics (PET)",
"ProductionCounts": 457615
}, {
"Part": "1.0 L Margarita Mix/PET",
"ProductionCounts": 660982
}, {
"Part": "other",
"ProductionCounts": 1571985
}]
}, ],
"dateArray": ["2011-01-01", "2011-02-01", "2011-03-01", "2011-04-01", "2011-05-01", "2011-06-01", "2011-07-01", "2011-08-01", "2011-09-01", "2011-10-01", "2011-11-01"],
"xAxis": "Part",
"yAxis": "ProductionCounts",
"interestingMoments": []
};
console.log(data.xAxis);
console.log(data.yAxis);
答
jsonData.data[0].data[0][jsonData.xAxis]
和jsonData.data[0].data[0][jsonData.yAxis]
答
你应该使用JSON这样
var a = {
"data": [{
"data": [{
"Part": "1.75 L ICON (Glass)",
"ProductionCounts": 1012620
}, {
"Part": "1.75 L Marg Mix (PET)",
"ProductionCounts": 1003278
}, {
"Part": "1.75 L Authentics (PET)",
"ProductionCounts": 457615
}, {
"Part": "1.0 L Margarita Mix/PET",
"ProductionCounts": 660982
}, {
"Part": "other",
"ProductionCounts": 1571985
}]
}, ],
"dateArray": ["2011-01-01", "2011-02-01", "2011-03-01", "2011-04-01", "2011-05-01", "2011-06-01", "2011-07-01", "2011-08-01", "2011-09-01", "2011-10-01", "2011-11-01"],
"xAxis": "Part",
"yAxis": "ProductionCounts",
"interestingMoments": []
};
a.data[0].data[0][a.xAxis] // for access part values
a.data[0].data[0][a.yAxis] // for acsess ProductionCounts values
答
我会从冗余“数据”对象,解开它。
http://jsfiddle.net/turiyag/cQNPm/
它看起来更清洁之后,和工作得很好。您的JSON对象也失败了JSLint。在发布之前,请始终通过JSLint或类似产品运行您的代码。
log("jsonData.data[0][jsonData.yAxis]: " + jsonData.data[0][jsonData.yAxis]);