如何通过多个CC发送Gmail电子邮件：'s

Question

我在寻找一个关于如何使用多个CC发送Gmail电子邮件的快速示例：'s。任何人都可以提出一个示例代码片段？

Answer 1

我以前做的片段为您呈现了一段代码，演示了如何连接到SMTP服务器，构建电子邮件（在Cc字段中有几个地址），然后发送。希望评论的*应用可以使它容易理解。

from smtplib import SMTP_SSL 
from email.mime.text import MIMEText 

## The SMTP server details 

smtp_server = "smtp.gmail.com" 
smtp_port = 587 
smtp_username = "username" 
smtp_password = "password" 

## The email details 

from_address = "[email protected]" 
to_address = "[email protected]" 

cc_addresses = ["[email protected]", "[email protected]"] 

msg_subject = "This is the subject of the email" 

msg_body = """ 
This is some text for the email body. 
""" 

## Now we make the email 

msg = MIMEText(msg_body) # Create a Message object with the body text 

# Now add the headers 
msg['Subject'] = msg_subject 
msg['From'] = from_address 
msg['To'] = to_address 
msg['Cc'] = ', '.join(cc_addresses) # Comma separate multiple addresses 

## Now we can connect to the server and send the email 

s = SMTP_SSL(smtp_server, smtp_port) # Set up the connection to the SMTP server 
try: 
    s.set_debuglevel(True) # It's nice to see what's going on 

    s.ehlo() # identify ourselves, prompting server for supported features 

    # If we can encrypt this session, do it 
    if s.has_extn('STARTTLS'): 
     s.starttls() 
     s.ehlo() # re-identify ourselves over TLS connection 

    s.login(smtp_username, smtp_password) # Login 

    # Send the email. Note we have to give sendmail() the message as a string 
    # rather than a message object, so we need to do msg.as_string() 
    s.sendmail(from_address, to_address, msg.as_string()) 

finally: 
    s.quit() # Close the connection 

Here's the code above on pastie.org for easier reading

关于多个抄送地址的具体问题，你可以在上面的代码中看到，你需要用逗号分隔的电子邮件地址的串，而不是一个列表。

如果你想要的名称以及地址，您不妨使用email.utils.formataddr() function来帮助他们进入正确的格式：

>>> from email.utils import formataddr 
>>> addresses = [("John Doe", "[email protected]"), ("Jane Doe", "[email protected]")] 
>>> ', '.join([formataddr(address) for address in addresses]) 
'John Doe <[email protected]>, Jane Doe <[email protected]>' 

希望这会有所帮助，让我知道，如果你有任何问题。

Answer 2

如果您可以使用库，我强烈建议http://libgmail.sourceforge.net/，我过去曾经简单地使用过，而且使用起来非常简单。您必须在您的Gmail帐户中启用IMAP/POP3才能使用此功能。

至于代码段（我还没有机会尝试这个，如果我可以，我会编辑此）：

import smtplib 
from email.MIMEMultipart import MIMEMultipart 
from email.MIMEBase import MIMEBase 
from email.MIMEText import MIMEText 
from email import Encoders 
import os 

#EDIT THE NEXT TWO LINES 
gmail_user = "[email protected]" 
gmail_pwd = "your_password" 

def mail(to, subject, text, attach, cc): 
    msg = MIMEMultipart() 

    msg['From'] = gmail_user 
    msg['To'] = to 
    msg['Subject'] = subject 

    #THIS IS WHERE YOU PUT IN THE CC EMAILS 
    msg['Cc'] = cc 
    msg.attach(MIMEText(text)) 

    part = MIMEBase('application', 'octet-stream') 
    part.set_payload(open(attach, 'rb').read()) 
    Encoders.encode_base64(part) 
    part.add_header('Content-Disposition', 
      'attachment; filename="%s"' % os.path.basename(attach)) 
    msg.attach(part) 

    mailServer = smtplib.SMTP("smtp.gmail.com", 587) 
    mailServer.ehlo() 
    mailServer.starttls() 
    mailServer.ehlo() 
    mailServer.login(gmail_user, gmail_pwd) 
    mailServer.sendmail(gmail_user, to, msg.as_string()) 
    # Should be mailServer.quit(), but that crashes... 
    mailServer.close() 

mail("[email protected]", 
    "Hello from python!", 
    "This is a email sent with python") 

对于我修改this