如果条件没有执行
问题描述:
我想弄清楚我的对象是否被打了一点点宽容。但它不起作用。这里是我的代码:如果条件没有执行
public boolean isClicked(float x) {
if (Gdx.input.isTouched() && Gdx.graphics.getHeight() - Gdx.input.getY() >= this.getY() && Gdx.graphics.getHeight() - Gdx.input.getY() <= this.getY() + this.getHeight() && this.getWidth() >= Gdx.input.getX() && x < this.getY() + this.getHeight() * 1.2f && x > this.getY() - this.getHeight() * .2f) {
return true;
}
return false;
答
总是试图以这种方式使用条件和使用托架多个条件:
if (Gdx.input.isTouched() && ((Gdx.graphics.getHeight() - Gdx.input.getY()) >= this.getY()) && ((Gdx.graphics.getHeight() - Gdx.input.getY()) <= (this.getY() + this.getHeight())) && (this.getWidth() >= Gdx.input.getX()) && (x < ((this.getY() + this.getHeight()) * 1.2f)) && (x > ((this.getY() - this.getHeight()) * .2f))) {
return true;
}
return false;
答
你应该尝试和格式长线可读性和使用括号。
if (Gdx.input.isTouched()
&& (Gdx.graphics.getHeight() - Gdx.input.getY()) >= this.getY()
&& (Gdx.graphics.getHeight() - Gdx.input.getY()) <= (this.getY() + this.getHeight())
&& this.getWidth() >= Gdx.input.getX()
&& x < (this.getY() + this.getHeight() * 1.2f)
&& x > (this.getY() - this.getHeight() * .2f)
) {
return true;
}
这也让您注释掉的任何中间行的开头(如使用//)隔离问题。