需要PHP正则表达式的专家 - 字符串内，但使用通配符

Question

我有代码查找文本目前符合

$data=["as much as I like oranges, I like bananas better", 
"there's no rest for the wicked", 
"the further I move from my target, the further I get", 
"just because I like that song, does not mean I will buy it"]; 

if (stripos($data[1], 'just because I') !== false) { 
     $line=str_ireplace('just because I','*'.just because I.'*',$data[1]); 
     break; 
    } 

这样简单地匹配包含文本的任何一句话。但我想要它做的是匹配一个通配符，所以它可以检测句型。因此，例如它可以检测到：

​​

希望这是可以理解的。它还需要匹配句子中出现的文本的位置，并通过在开始和结束处添加*来标记它。

Answer 1

可以使用preg_replace代替str_ireplace：

$data = ["as much as I like oranges, I like bananas better", 
     "there's no rest for the wicked", 
     "the further I move from my target, the further I get", 
     "just because I like that song, does not mean I will buy it", 
     "the further I move from my target, the further I get"]; 
$pattern = '/(.*)(just because I .* does not mean)(.*)/i'; 
$replacement = '$1*$2*$3'; 
foreach ($data as $data_) { 
    $line = preg_replace($pattern, $replacement, $data_, -1, $count)."\n"; 
    if ($count > 0) { 
    break; 
    } 
} 
echo $line; 

返回结果：

*just because I like that song, does not mean* I will buy it 

的count变量将包含由更换的次数，按文档。我添加了它，因为它看起来像你想在第一次替换之后跳出循环。