发送参数的方法 - NSTimeInterval

Question

我想一个NSTimeInterval送入将从在后台线程上运行的方法，在主线程上运行的方法。不幸的是，我得到这个错误：

Sending 'NSTimeInterval' (aka 'double') to parameter of incompatible type 'id' 

这是我的代码 - 任何想法发生了什么错？

首先，我安装我的NSTimerInterval，并调用performSelectorOnMainThread：

NSTimeInterval delayBetweenIntAdsNSTimeInterval = [responseStringTimeBetweenAds doubleValue]; 
[self performSelectorOnMainThread:@selector(startTimerForAds:) withObject:delayBetweenIntAdsNSTimeInterval waitUntilDone:NO]; 

，这里是我的方法的代码我打电话：

-(void)startTimerForAds:(NSTimeInterval)intervalBetweenAds { 
} 

上做什么用的是走错了任何的想法？

感谢，

UPDATE

我打电话：

[self performSelectorOnMainThread:@selector(startTimerForAds:) withObject:@(delayBetweenIntAds) waitUntilDone:NO]; 

这里是方法：

-(void)startTimerForAds:(NSInteger *)intervalBetweenIntAdsInteger { 
} 

但在该呼叫（在对象）， XCode显示：

Illegal type 'NSInteger *' (aka 'int *') used in a boxed expression 

，它显示了在[intervalBetweenIntAdsInteger的doubleValue]：

Bad receiver type 'NSInteger *' (aka 'int *') 

Answer 1

NSTimeInterval不是一个对象。尝试的NSNumber，应该这样做：

NSTimeInterval delayBetweenIntAdsNSTimeInterval = [responseStringTimeBetweenAds doubleValue]; 
[self performSelectorOnMainThread:@selector(startTimerForAds:) withObject:@(delayBetweenIntAdsNSTimeInterval) waitUntilDone:NO]; 


-(void)startTimerForAds:(NSNumber *)intervalBetweenAds { 

    NSTimeInterval i = [intervalBetweenAds doubleValue]; 

} 

因为你更新的更新：

[self performSelectorOnMainThread:@selector(startTimerForAds:) withObject:@(delayBetweenIntAds) waitUntilDone:NO]; 

-(void)startTimerForAds:(NSNumber *)intervalBetweenAds { 
    int i = [intervalBetweenAds intValue]; 
}