莫尔斯电码转换器循环错误

Question

编辑：现在完全修复。

编辑：好，所以现在我把它改变'... --- ...'到'sos'（yippee！）但是由于某种原因，当我输入时它给了我一个KeyError'... --- .../... --- ...'。 这应该给我'sos sos'，但我得到''的KeyError。 我认为这是因为在'/'之后，程序将其视为调用当前键的字典值的触发器。问题在于，由于前面的字符是'/'，当时的当前键是空白的。我将如何解决这个问题？ 谢谢。我很新的编程与蟒蛇（以及，一般编程，真的......），今天我有一个明智的想法，使莫尔斯电码转换器。

我有“纯文本莫尔斯电码”工作完美，但“莫尔斯电码纯文本”？

并非如此。

问题是，当我运行程序时，它不给我任何东西，它只是打破了它的循环（就像我告诉过的那样），没有任何东西回来给我。

如果你们能帮助我，我会非常感激。

哦，'decode_dict'是我做的一个字典，它将莫尔斯电码值与纯文本相关联。 例如，

decoding_dict = {'...' : 's' , '---' : 'o'} 

等等等等。

def decode(text): 
    text += ' ' 
    #I have it set up to trigger when there's a space, hence this. 
    global key 
    global decoded_text 
    #I thought maybe this would fix it, it didn't. :(
    key = '' 
    decoded_text = '' 
    for i in text: 
     if i == '.': 
      key += i #This adds a '.' to the key to reference later. 
      continue 
     elif i == '-': 
      key += i #See above comment. 
      continue 
     elif i == ' ': 
      decoded_text += decoding_dict[key] 
      text = text[(len(key) + 1) :] 
      key = '' #Calls the value of the key, cuts out the used text, and resets key. 
      continue 
     elif i == '/': 
      decoded_text += decoding_dict['/'] 
      continue #In morse code, a '/' is a ' ' and that's in the dict. 
     elif text == '': 
      print "Result: " + decoded_text 
      break #This is basically the end of the loop 
     else: 
      print "Error, please try again." 
      break 

现在，当我用'... --- ...'运行它时，它会回到开头，并且不会打印任何东西。 （通过开始，我的意思是我事先做好的菜单）

Answer 1

根据您的代码尝试是这样的： -

def decode(text): 
    text += '$' 
    #I have it set up to trigger when there's a space, hence this. 
    global key 
    global decoded_text 
    #I thought maybe this would fix it, it didn't. :(
    key = '' 
    decoded_text = '' 
    for i in text: 
     if i == '.': 
      key += i #This adds a '.' to the key to reference later. 
      continue 
     elif i == '-': 
      key += i #See above comment. 
      continue 
     elif i == ' ': 
      decoded_text += decoding_dict[key] 
      text = text[(len(key) + 1) :] 
      key = '' #Calls the value of the key, cuts out the used text, and resets key. 
      continue 
     elif i == '/': 
      decoded_text += decoding_dict['/'] 
      continue #In morse code, a '/' is a ' ' and that's in the dict. 
     elif text == '$': 
      print "Result: " + decoded_text 
      break #This is basically the end of the loop 
     else: 
      print "Error, please try again." 
      break 

根据我的建议试试这个： -

def decode(text): 
    error = False 
    #I have it set up to trigger when there's a space, hence this. 
    global key 
    global decoded_text 
    #I thought maybe this would fix it, it didn't. :(
    key = '' 
    decoded_text = '' 
    for i in text: 
     if i == '.': 
      key += i #This adds a '.' to the key to reference later. 
      continue 
     elif i == '-': 
      key += i #See above comment. 
      continue 
     elif i == ' ': 
      decoded_text += decoding_dict[key] 
      text = text[(len(key) + 1) :] 
      key = '' #Calls the value of the key, cuts out the used text, and resets key. 
      continue 
     elif i == '/': 
      decoded_text += decoding_dict['/'] 
      continue #In morse code, a '/' is a ' ' and that's in the dict. 
     else: 
      print "Error, please try again." 
      error = True 
      break 
    else: 
     If not error: 
      print "Result: " + decoded_text 

last else用于替代if else

Answer 2

for循环仅考虑初始值text。对循环中的text所做的更改不起作用，因为text是一个字符串，并且字符串是不可变的，所以您的修改不会修改要迭代的原始对象。结果是你的循环遍历所有原始的text，完成循环而没有输入你的break条件。

只需摆脱if text == ''检查并将“打印结果”行移至for循环外。您不需要“删除使用过的文本”，因为当您到达想要执行该操作的时候，您已经遍历整个密钥。如果你只是选择离开的地方，那么无论如何你将开始在下一个循环迭代中解析下一个莫尔斯字母。

Answer 3

假设空间' '是在输入指定的隔板，可以使用这样的：

decoding_dict = {'...' : 's' , '---' : 'o'} 
my_text = '... --- ...' 
print(''.join(list(map(lambda x: decoding_dict.get(x, None), 

---

输出：

---

sos 

至于上面的代码中，有有几个问题：

• 修改“文本”，同时迭代它
• 检查文本==''，这从来没有发生。因此，结果从不打印。

试试这个：

def decode(text): 
    text += ' ' 
    #I have it set up to trigger when there's a space, hence this. 
    global key 
    global decoded_text 
    #I thought maybe this would fix it, it didn't. :(
    key = '' 
    decoded_text = '' 
    for i in text: 
     if i == '.': 
      key += i #This adds a '.' to the key to reference later. 
      continue 
     elif i == '-': 
      key += i #See above comment. 
      continue 
     elif i == ' ': 
      decoded_text += decoding_dict[key] 
      key = '' #Calls the value of the key, cuts out the used text, and resets key. 
      continue 
     elif i == '/': 
      decoded_text += decoding_dict['/'] 
      continue #In morse code, a '/' is a ' ' and that's in the dict. 
     else: 
      print("Error, please try again.") 
      break 
    print("Result: " + decoded_text) 

---

电话：decode(my_text) 输出：

---

Result: sos