在android应用程序中没有得到url的响应

Question

我正在开发一个android应用程序，其中我有一个listview中的5个项目。我不能在ListView去取数据，...我已经尝试了所有的东西,,,但没有什么是代雷在ListView

我的网址是

http://harpreetvir.web708.discountasp.net/PMevents/XmlRecord/AddEvent.xml

我DDMS logcat的是http://pastebin.com/YH0JWiRJ

任何人都可以帮忙吗？

Answer 1

请通过以下代码发布。

 try { 
      HttpClient client = new DefaultHttpClient(); 
      String postURL = "http://harpreetvir.web708.discountasp.net/PMevents/XmlRecord/AddEvent.xml"; 
      HttpGet post = new HttpGet(postURL); 
      HttpResponse responsePOST = client.execute(post); 
      HttpEntity resEntity = responsePOST.getEntity(); 
      String str1=EntityUtils.toString(resEntity); 
      str1=str1.trim(); 
      parsing(str1); 
     } 
     catch (XmlPullParserException e) { 
     e.printStackTrace(); 
     } catch (IOException e) { 
     e.printStackTrace(); 
     } 
     public void parsing(String str1) throws XmlPullParserException, IOException{ 
     XmlPullParserFactory factory = XmlPullParserFactory.newInstance(); 
     factory.setNamespaceAware(true); 
     XmlPullParser xpp = factory.newPullParser(); 
     xpp.setInput(new StringReader (str1)); 
     int eventType = xpp.getEventType(); 
     while (eventType != XmlPullParser.END_DOCUMENT) { 
     String str; 
     if(eventType == XmlPullParser.START_DOCUMENT) { 
      System.out.println("Start document"); 
     } else if(eventType == XmlPullParser.START_TAG) { 
      str = xpp.getName(); 
      System.out.println("Start tag "+str); 

     } else if(eventType == XmlPullParser.END_TAG) { 
      System.out.println("End tag "+xpp.getName()); 
     } else if(eventType == XmlPullParser.TEXT) { 
      System.out.println("Value= "+xpp.getText()); 
     } 
     eventType = xpp.next(); 
     } 
     System.out.println("End document"); 
    }