JSON返回null响应与jQuery $ .ajax
问题描述:
我想在ajax后获得响应,但总是返回NULL。
我在想,已经尝试了所有我可以......但希望有人能够解决它。首先十分感谢。如果需要更多信息,请告诉我。
注:PHP function not returning any data to JQuery ajax method - 这个环节并没有帮助我
这里是jQuery代码:
var post_id=3;
$.ajax({
type: "POST",
url: "profile/ajax_get_new_posts",
data: { post_id : post_id },
dataType: 'json',
success: function(data){
console.log(data);
var current_content = $("ol#posts_container").html();
$("ol#posts_container").html(data.content + current_content);
}
});
资料/ ajax_get_new_posts(它名为.php)
function ajax_get_new_posts(){
header('Content-Type: application/json');
$post_id=$this->input->post('post_id');
$chat_messages_html='testing';
$result = array('status' => 'ok', 'content' => $chat_messages_html);
$result=json_encode($result);
return ($result);
exit();
}
如果我试着用var_dump($ result); die();给我正确的结果:
string(38) "{"status":"ok","content":"samoletite"}"
在响应头给我的Content-Length:0(它正在测试在本地主机上......不www.mywebsite)
Remote Address:[::1]:80
Request URL:http://www.mywebsite/bg/profile/ajax_get_new_posts
Request Method:POST
Status Code:200 OK
Request Headersview source
Accept:application/json, text/javascript, */*; q=0.01
Accept-Encoding:gzip,deflate
Accept-Language:en-US,en;q=0.8
Connection:keep-alive
Content-Length:9
Content-Type:application/x-www-form-urlencoded
Host:localhost
Origin:http://localhost
Referer:http://www.mywebsite/bg/profile
User-Agent:Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/38.0.2125.111 Safari/537.36
X-Requested-With:XMLHttpRequest
Form Dataview sourceview URL encoded
post_id:3
Response Headersview source
Connection:Keep-Alive
Content-Length:0
Content-Type:application/json
Date:Fri, 31 Oct 2014 13:24:56 GMT
Keep-Alive:timeout=5, max=97
.......
CONSOLE.LOG给我:
null --->ajaxPostProfile.js:28
Uncaught TypeError: Cannot read property 'content' of null --->ajaxPostProfile.js:31
答
而是使用return ($result);
,使用echo
。像这样:
function ajax_get_new_posts(){
header('Content-Type: application/json');
$post_id=$this->input->post('post_id');
$chat_messages_html='testing';
$result = array('status' => 'ok', 'content' => $chat_messages_html);
$result=json_encode($result);
echo $result;
exit();
}
并再次测试。
答
你可以在PHP中使用下面的语法返回JSON数据:
header('Content-Type: application/json');
echo json_encode($result);
谢谢你非常非常....谢谢你救了我的时间从10个小时寻找解决方案。干杯! – 2014-10-31 13:48:26
不客气!请将此答案设为正确。谢谢。 – 2014-10-31 14:09:33