在打字稿，你怎么了，你键入特定的键对象常量

Question

所以我有这个数据结构

export interface StoreData { 
    msdb: {[tableName: string]: List<StoreModel>}; 
} 

，但我想只允许（并获得IntelliSence）对我的表名特定字符串的值。 所以，我试图像下面，但它没有工作：

var tableNames:'table_campaigns' | 'table_resources' 
export interface StoreData { 
    msdb: {[tableName]: List<StoreModel>}; 
} 

也试过，没有运气

interface IMyTables { 
    'table_campaigns: string 
    'table_resources: string; 
} 

type MyTables = keyof IMyTables; 

export interface StoreData { 
    participants: { [key: number]: any }; 
    threads: { [key: number]: any }; 
    messages: { [key: number]: any }; 
    msdb: {MyTables: List<StoreModel>}; 
} 

也试过

type allMyTables = 'table_campaigns' | 'table_resources' 

export interface StoreData { 
    msdb: {[tableName: allMyTables]: List<StoreModel>}; 
} 




Thanks for reading, 

Sean 

Answer 1

感谢杰夫，即做到了：

export interface StoreData { 
    participants: { [key: number]: any }; 
    threads: { [key: number]: any }; 
    messages: { [key: number]: any }; 
    msdb: { 
     'table_campaigns': List<StoreModel>; 
     'table_resources': List<StoreModel>; 
    }; 
}