Underscore.js分组对象

问题描述：

是更多钞票，以组对象，并结合Underscore.js所有属性是这样的：Underscore.js分组对象

[ 
    { menu: "Setting", role: "admin" }, 
    { menu: "Setting", role: "user" }, 
    { menu: "Setting", role: "developer" }, 
    { menu: "Application", role: "admin" }, 
    { menu: "Application", role: "user" }, 
]

弄成这个样子：

[ 
    { menu: "Setting", admin: "OK", user: "OK", developer: "OK"}, 
    { menu: "Application", admin: "OK", user: "OK"}, 
]

是的，也有可能与常规的*S一样。 – Adam

是的，我一直在尝试与常规的JS，但我最终与循环，需要时间和内存，所以我想寻找替代品，如underscore.js :) – stkertix

答

_.map(_.groupBy(arr, 'menu'), function(roles, menu) { 
    var entry = {menu: menu}; 
    _.each(roles, function(role) { entry[role.role] = "OK"; }); 
    return entry; 
})

我假设你后面的输出是：

[ 
    { "menu": "Setting", "admin": "OK", "user": "OK", "developer": "OK" }, 
    { "menu": "Application", "admin": "OK", "user": "OK" } 
]

woaah，它适用于这样一个简单的脚本。感谢您的回答。：d – stkertix

Underscore.js分组对象

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