java如果语句条件被忽略

Question

我的计划是使蛇游戏蛇被向上和向下移动，不会左右移动

package snake2; 

import java.awt.BorderLayout; 
import java.awt.Frame; 
import java.awt.Graphics; 
import java.awt.Label; 
import java.awt.event.MouseEvent; 
import java.awt.event.MouseListener; 
import javax.swing.JOptionPane; 



public class Snake extends Frame implements MouseListener{ 

@Override 
public void mouseClicked(MouseEvent e) { 


    if (e.getX()>x[0]) 
    { 
      incx=1; 
      incy=0; 
    } 
    if (e.getX()<x[0]) 
    { 
     incx=-1; 
     incy=0; 
    } 
    if(e.getY()>y[0]) 
    { 
     incx=0;  
     incy=1; 
    } 
    if(e.getY()<y[0]) 
    { 
     incx=0; 
     incy=-1; 
    } 

} 


@Override 
public void mousePressed(MouseEvent e) { 
    throw new UnsupportedOperationException("Not supported yet."); 
} 

@Override 
public void mouseReleased(MouseEvent e) { 
    throw new UnsupportedOperationException("Not supported yet."); 
} 

@Override 
public void mouseEntered(MouseEvent e) { 
    throw new UnsupportedOperationException("Not supported yet."); 
} 

@Override 
public void mouseExited(MouseEvent e) { 
    throw new UnsupportedOperationException("Not supported yet."); 
} 
    int incx=1,incy=0; 
int[] x = new int[300]; 
int[] y = new int [300]; 
int len=5; 
public Label l; 

public Snake() 
{ 
    setSize(500, 500); 
    setVisible(true); 
    this.addMouseListener(this); 
    l = new Label("snake lenght ="+ len); 
    add(l,BorderLayout.SOUTH); 
    x[0]=100; 
    y[0]=100; 

} 

public static void main(String[] args) 
{ 

    Snake s = new Snake(); 
    move m = new move(); 
    m.ptr=s; 
    m.start(); 
} 
public void paint(Graphics g) 
{ 
    for(int i=0 ; i<=len;i++) 
    g.fillRect(x[i], y[i], 10, 10);   
} 
public void shift() 
{ 
    for (int z=len;z>0;z--) 
    { 
      x[z]=x[z-1]; 
      y[z]=y[z-1]; 
    } 


} 
} 

class move extends Thread 
{ 

    Snake ptr; 

    int count=0; 

    public void run() 
{ 
    for (;;) 
    { 
      ptr.shift(); 
      count++; 
      ptr.x[0]=ptr.x[0]+ptr.incx*10; 
      ptr.y[0]=ptr.y[0]+ptr.incy*10; 
      ptr.repaint(); 
      try{sleep(150);}catch(Exception a){} 

      if(count%5==0){ 
      ptr.len++;} 
      ptr. l.setText("snake lenght ="+ ptr.len); 

      for (int z = ptr.len; z > 0; z--) { 

    if ((z > 4) && (ptr.x[0] == ptr.x[z]) && (ptr.y[0] == ptr.y[z])) { 
     JOptionPane.showConfirmDialog(null, "You lost"); 
      } 
     } 

    if (ptr.y[0] >500) { 
     JOptionPane.showConfirmDialog(null, "You lost"); 
    } 

    if (ptr.y[0] < 0) { 
     JOptionPane.showConfirmDialog(null, "You lost"); 
    } 

    if (ptr.x[0] > 500) { 
     JOptionPane.showConfirmDialog(null, "You lost"); 
    } 

    if (ptr.x[0] < 0) { 
     JOptionPane.showConfirmDialog(null, "You lost"); 
    } 


     } 

    } 

} 

在我的程序，它跳过第2如果问题语句，它只是跳过X，如果我用Y更改X，则跳过Y并执行X并开始左右移动并停止上下移动。

Answer 1

你需要如下检查，因为如果y轴的改变，那么你重新在x所做的更改和鼠标可以沿着X和Y轴同时放

if (e.getX()>x[0]) 
{ 
    incx=1; 
} else if (e.getX()<x[0]) 
{ 
    incx=-1; 
} 
if(e.getY()>y[0]) 
{ 
    incy=1; 
} else if(e.getY()<y[0]) 
{ 
    incy=-1; 
}