查询结束开始与
问题描述:
我必须尝试查找基于搜索的结果,这应该是首发,但我找不到QueryOver
其中有startwith,有没有其他方法?查询结束开始与
public IEnumerable<Company> Find(string keyword)
{
var sesion = SessionController.CurrentSession;
return sesion.QueryOver<Company>()
.Where(
Restrictions.On<Company>(x => x.CompanyName).IsLike("%" + keyword + "%") ||
Restrictions.On<Company>(x => x.Id).IsLike("%" + keyword + "%")
)
.List<Company>();
}
答
的方式,通过QueryOver
基础设施的支持将是使用明确MatchMode
:
sesion
.QueryOver<Company>()
.Where
(
Restrictions.On<Company>(x => x.CompanyName).IsLike(keyword, MatchMode.Start) ||
Restrictions.On<Company>(x => x.Id ).IsLike(keyword, MatchMode.Start)
)
.List<Company>();
但有极少数代码(在Restrictions.On
风格的自定义扩展)我们甚至可以做到这一点语法:
...
.Where
(
Restrict.On<Contact>(x => x.CompanyName).StartsWith(keyword) ||
Restrict.On<Contact>(x => x.Id ).StartsWith(keyword)
)
而且Restrict
的定义:
public static class Restrict
{
public static StringRestrictionBuilder<T> On<T>(Expression<Func<T, object>> expr)
{
return new StringRestrictionBuilder<T>(expr);
}
public class StringRestrictionBuilder<T>
{
readonly Expression<Func<T, object>> _expression;
public StringRestrictionBuilder(Expression<Func<T, object>> expression)
{
_expression = expression;
}
public AbstractCriterion StartsWith(string value)
{
return Restrictions.On(_expression).IsLike(value, MatchMode.Start);
}
public AbstractCriterion Contains(string value)
{
return Restrictions.On(_expression).IsLike(value, MatchMode.Anywhere);
}
public AbstractCriterion EndsWith(string value)
{
return Restrictions.On(_expression).IsLike(value, MatchMode.End);
}
}
}
你的意思是除了删除IsLike限制中的前导%吗? – jbl